Solve the simultaneous equation p=3q 4p₅q =14 a₆2 c₆

Given the first equation $p = 3q$.
Substitute this expression for $p$ into the second equation $4p - 5q = 14$:

$$4(3q) - 5q = 14$$

$$12q - 5q = 14$$ $$7q = 14$$ $$q = \frac{14}{7}$$ $$q = 2$$

Using $p = 3q$:

$$p = 3(2)$$ $$p = 6$$

The solution to the simultaneous equations is:
$p = \boxed{6}$
$q = \boxed{2}$