Since DB = BE (given), DBE is an isosceles triangle. In an isosceles triangle, the angles opposite the equal sides are equal.

Step 2: Use the property of the isosceles triangle DBE. Since DB = BE (given), DBE is an isosceles triangle. In an isosceles triangle, the angles opposite the equal sides are equal. Therefore, ∠ BDE = ∠ BED. Step 3: Combine angle relationships. From Step 1, we have ∠ CBE = ∠ BDE (tangent-chord theorem). From Step 2, we have ∠ BDE = ∠ BED. Combining these two equalities, we get ∠ CBE = ∠ BDE = ∠ BED. Thus, ∠ CBE = ∠ BED. Step 4: Prove congruence using Angle-Angle-Side (AAS) criterion.

Since DB = BE (given), DBE is an isosceles triangle. In an isosceles triangle, the angles opposite the equal sides are equal.

Step 2: Use the property of the isosceles triangle DBE. Since DB = BE (given), DBE is an isosceles triangle. In an isosceles triangle, the angles opposite the equal sides are equal. Therefore, ∠ BDE = ∠ BED. Step 3: Combine angle relationships. From Step 1, we have ∠ CBE = ∠ BDE (tangent-chord theorem). From Step 2, we have ∠ BDE = ∠ BED. Combining these two equalities, we get ∠ CBE = ∠ BDE = ∠ BED. Thus, ∠ CBE = ∠ BED. Step 4: Prove congruence using Angle-Angle-Side (AAS) criterion.

Solved: Since DB = BE (given), DBE is an isosceles…

Use the property of the isosceles triangle $\triangle DBE$ .
Since $DB = BE$ (given), $\triangle DBE$ is an isosceles triangle. In an isosceles triangle, the angles opposite the equal sides are equal.
Therefore, $\angle BDE = \angle BED$ .
Combine angle relationships.
From Step 1, we have $\angle CBE = \angle BDE$ (tangent-chord theorem).
From Step 2, we have $\angle BDE = \angle BED$ .
Combining these two equalities, we get $\angle CBE = \angle BDE = \angle BED$ .
Thus, $\angle CBE = \angle BED$ .
Prove congruence using Angle-Angle-Side (AAS) criterion.

Since DB = BE (given), DBE is an isosceles triangle. In an isosceles triangle, the angles opposite the equal sides are equal.

Step-by-step solution

Use the property of the isosceles triangle $\triangle DBE$ .

Combine angle relationships.

Prove congruence using Angle-Angle-Side (AAS) criterion.

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Since DB = BE (given), DBE is an isosceles triangle. In an isosceles triangle, the angles opposite the equal sides are equal.

Step-by-step solution

Use the property of the isosceles triangle △DBE\triangle DBE△DBE.

Combine angle relationships.

Prove congruence using Angle-Angle-Side (AAS) criterion.

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Use the property of the isosceles triangle $\triangle DBE$ .