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Describe the single transformation represented by the composition of a reflection on the line y = -x and a rotation about the origin through 180 degrees. Then, find the image of triangle ABC with vert

Mathematics

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2 parts
1

Reflection on the line y=x\text{Reflection on the line } y=x

2

A'(2, 1), B'(3, -4), C'(5, 3)

Here's the solution to the transformation problem:

First, let's define the individual transformations:

  • R (Reflection on the line y=−xy = -x): A point (x,y)(x, y) is transformed to (−y,−x)(-y, -x).
  • S (Rotation about the origin through 180∘180^\circ): A point (x,y)(x, y) is transformed to (−x,−y)(-x, -y).

The combined transformation is RoS, which means we apply S first, then R.

Part 1: Find the single transformation represented by RoS.

Let's apply the transformations to a general point (x,y)(x, y):

  1. Apply S to (x,y)(x, y): S(x,y)=(−x,−y)S(x, y) = (-x, -y)
  2. Now, apply R to the result (−x,−y)(-x, -y). Let x′=−xx' = -x and y′=−yy' = -y. Using the rule for R, which is (x′,y′)→(−y′,−x′)(x', y') \to (-y', -x'), we get: R(−x,−y)=(−(−y),−(−x))=(y,x)R(-x, -y) = (-(-y), -(-x)) = (y, x)

So, the combined transformation RoS maps a point (x,y)(x, y) to (y,x)(y, x).
This single transformation is a reflection on the line y=xy = x.

The single transformation represented by RoS is Reflection on the line y=x\boxed{\text{Reflection on the line } y=x}.

Part 2: Find the co-ordinates of the vertices of the image of △ABC\triangle ABC.

The vertices of △ABC\triangle ABC are A(1, 2), B(-4, 3), and C(3, 5).
We use the single transformation rule RoS(x,y)=(y,x)RoS(x, y) = (y, x) to find the image coordinates.

  • For vertex A(1, 2): A′=RoS(1,2)=(2,1)A' = RoS(1, 2) = (2, 1)
  • For vertex B(-4, 3): B′=RoS(−4,3)=(3,−4)B' = RoS(-4, 3) = (3, -4)
  • For vertex C(3, 5): C′=RoS(3,5)=(5,3)C' = RoS(3, 5) = (5, 3)

The coordinates of the image △A′B′C′\triangle A'B'C' are A′(2,1),B′(3,−4),C′(5,3)\boxed{A'(2, 1), B'(3, -4), C'(5, 3)}.

Part 3: Present △ABC\triangle ABC and its image on the same graph paper.

To present this on graph paper, you would plot the following points and connect them to form the triangles:

  • Original Triangle △ABC\triangle ABC:
    • A(1, 2)
    • B(-4, 3)
    • C(3, 5)
  • Image Triangle △A′B′C′\triangle A'B'C':
    • A'(2, 1)
    • B'(3, -4)
    • C'(5, 3)

Draw the line y=xy=x on your graph paper. You will observe that △A′B′C′\triangle A'B'C' is the reflection of △ABC\triangle ABC across the line y=xy=x.

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