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Find the size of angles w, x, y and z, giving a reason for your answer in each case.

Mathematics

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Here are the solutions for the geometry problems.

Question 2

a)
The diagram shows two parallel horizontal lines intersected by two transversals, forming an isosceles triangle.

  1. Find the size of angle zz.

    Angle zz and the given 60∘60^\circ angle are alternate interior angles because they are between parallel lines and on opposite sides of a transversal. Alternate interior angles are equal.

    z=60∘z = 60^\circ

    The size of angle zz is 60∘\boxed{\text{60}^\circ} (Reason: Alternate interior angles).

  2. Find the size of angle yy.

    The triangle is isosceles, and angle zz is one of its base angles. Therefore, the other base angle (at the top-left vertex of the triangle) is also 60∘60^\circ. The sum of angles in a triangle is 180∘180^\circ.

    y+60∘+60∘=180∘y + 60^\circ + 60^\circ = 180^\circ y+120∘=180∘y + 120^\circ = 180^\circ y=180∘−120∘y = 180^\circ - 120^\circ y=60∘y = 60^\circ

    The size of angle yy is 60∘\boxed{\text{60}^\circ} (Reason: Sum of angles in an isosceles triangle).

  3. Find the size of angle xx.

    Angle xx and angle yy are vertically opposite angles. Vertically opposite angles are equal.

    x=yx = y x=60∘x = 60^\circ

    The size of angle xx is 60∘\boxed{\text{60}^\circ} (Reason: Vertically opposite angles).

  4. Find the size of angle ww.

    Angle ww and the top-left base angle of the isosceles triangle (which is 60∘60^\circ) are alternate interior angles because they are between parallel lines and on opposite sides of a transversal. Alternate interior angles are equal.

    w=60∘w = 60^\circ

    The size of angle ww is 60∘\boxed{\text{60}^\circ} (Reason: Alternate interior angles).

    b)
    In the diagram, PQ is parallel to RS, and PY = PZ.

  5. Find the interior angle at R.

    The angle 140∘140^\circ and the interior angle ∠PRS\angle PRS form a linear pair on a straight line. Angles on a straight line sum to 180∘180^\circ.

    ∠PRS=180∘−140∘\angle PRS = 180^\circ - 140^\circ ∠PRS=40∘\angle PRS = 40^\circ
  6. Find angle ∠YPZ\angle YPZ.

    Since PQ is parallel to RS, angle ∠YPZ\angle YPZ and angle ∠PRS\angle PRS are alternate interior angles. Alternate interior angles are equal.

    ∠YPZ=∠PRS\angle YPZ = \angle PRS ∠YPZ=40∘\angle YPZ = 40^\circ
  7. Find the base angles of triangle PYZ.

    Given that PY = PZ, triangle PYZ is an isosceles triangle. The base angles opposite the equal sides are equal, so ∠PYZ=∠PZY\angle PYZ = \angle PZY. The sum of angles in a triangle is 180∘180^\circ.

    ∠YPZ+∠PYZ+∠PZY=180∘\angle YPZ + \angle PYZ + \angle PZY = 180^\circ 40∘+∠PZY+∠PZY=180∘40^\circ + \angle PZY + \angle PZY = 180^\circ 40∘+2⋅∠PZY=180∘40^\circ + 2 \cdot \angle PZY = 180^\circ
  8. Solve for ∠PZY\angle PZY, which is xx.

    2⋅∠PZY=180∘−40∘2 \cdot \angle PZY = 180^\circ - 40^\circ 2⋅∠PZY=140∘2 \cdot \angle PZY = 140^\circ ∠PZY=140∘2\angle PZY = \frac{140^\circ}{2} ∠PZY=70∘\angle PZY = 70^\circ

    Therefore, the size of angle xx is 70∘\boxed{\text{70}^\circ}.

    Question 3

    a)
    The diagram shows a trapezium with parallel top and bottom sides. The angles are given in terms of xx. For parallel lines intersected by a transversal, consecutive interior angles sum to 180∘180^\circ.

  9. Calculate xx using the angles on the left transversal.

    The angles 2x2x (top left) and 2x+10∘2x + 10^\circ (bottom left) are consecutive interior angles.

    2x+(2x+10∘)=180∘2x + (2x + 10^\circ) = 180^\circ 4x+10∘=180∘4x + 10^\circ = 180^\circ 4x=180∘−10∘4x = 180^\circ - 10^\circ 4x=170∘4x = 170^\circ x=170∘4x = \frac{170^\circ}{4} x=42.5∘x = 42.5^\circ
  10. Calculate xx using the angles on the right transversal.

    The angles 3x−20∘3x - 20^\circ (top right) and 2x2x (bottom right) are consecutive interior angles.

    (3x−20∘)+2x=180∘(3x - 20^\circ) + 2x = 180^\circ 5x−20∘=180∘5x - 20^\circ = 180^\circ 5x=180∘+20∘5x = 180^\circ + 20^\circ 5x=200∘5x = 200^\circ x=200∘5x = \frac{200^\circ}{5} x=40∘x = 40^\circ
  11. Identify the inconsistency.

    The problem contains an inconsistency, as the value of xx differs depending on which pair of consecutive interior angles is used (42.5∘42.5^\circ from the left side and 40∘40^\circ from the right side). Therefore, a unique value for xx cannot be determined from the given information.

  12. Provide a value with a note.

    Since a unique value for xx cannot be determined due to the inconsistency in the problem statement, we will provide the value derived from the left side as an example.
    The value of xx is 42.5∘\boxed{\text{42.5}^\circ} (Note: The problem contains an inconsistency, leading to different values of xx depending on the transversal used).

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