Sketch and answer for questions 34

Mathematics

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Here are the construction steps for question 34:

34. Construct a parabola given the focus and directrix.

A parabola is defined as the locus of points that are equidistant from a fixed point (the focus) and a fixed line (the directrix).

Construction Steps:

  1. Draw a line DD' to represent the directrix.

    Mark a point F (the focus) not on the line DD'.

  2. Draw a line through F perpendicular to DD'.

    This line is the axis of the parabola. Let it intersect DD' at point K.

  3. Locate the vertex V of the parabola.

    The vertex V is the midpoint of the segment FK.

  4. Choose several points P1,P2,P3,…P_1, P_2, P_3, \dots on the axis, starting from V and moving away from F.

  5. Through each point PiP_i, draw a line LiL_i perpendicular to the axis (and thus parallel to the directrix).

  6. For each point PiP_i, measure the distance KPiKP_i (the perpendicular distance from the directrix to PiP_i).

  7. With F as the center and radius equal to KPiKP_i, draw arcs that intersect the line LiL_i at two points, say QiQ_i and Qi′Q'_i.

    These points QiQ_i and Qi′Q'_i are on the parabola because FQi=KPiFQ_i = KP_i.

  8. Connect the vertex V and the points Qi,Qi′Q_i, Q'_i with a smooth curve to form the parabola.

    Sketch Description:
    The sketch will show a horizontal line labeled DD' (the directrix). Above this line, there will be a point F (the focus). A vertical line, the axis of the parabola, will pass through F and be perpendicular to DD', intersecting DD' at point K. The vertex V will be marked as the midpoint of FK. Several horizontal lines (L1,L2,…L_1, L_2, \dots) parallel to DD' will be drawn above DD', intersecting the axis at points P1,P2,…P_1, P_2, \dots. For each PiP_i, arcs will be drawn from F with radius KPiKP_i, intersecting the corresponding line LiL_i at two points (Qi,Qi′Q_i, Q'_i). A smooth, U-shaped curve, opening away from the directrix and passing through V and all the Qi,Qi′Q_i, Q'_i points, will represent the parabola.

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