Sketch the graph of: x/2 + y/3 = 1. Is the graph in Q1.1 a function or relation? Is the graph in Q1.1 continuous?

The equation is in the intercept form $\frac{x}{a} + \frac{y}{b} = 1$, where $a$ is the x-intercept and $b$ is the y-intercept.
From the given equation, $a = 2$ and $b = 3$.
So, the x-intercept is $(2, 0)$ and the y-intercept is $(0, 3)$.

To sketch the graph, plot the x-intercept at $(2, 0)$ on the x-axis and the y-intercept at $(0, 3)$ on the y-axis. Then, draw a straight line connecting these two points.
The graph is a straight line passing through $(2, 0)$ and $(0, 3)$.

The equation $\frac{x}{2} + \frac{y}{3} = 1$ can be rewritten to solve for $y$:

This is a linear equation in the form $y = mx + c$.

For every input value of $x$, there is exactly one output value of $y$. This means the graph passes the vertical line test.
Therefore, the graph is a function.

The graph of $\frac{x}{2} + \frac{y}{3} = 1$ is a straight line.

A straight line can be drawn without lifting the pen, meaning there are no breaks, jumps, or holes in the graph.
Therefore, the graph is continuous.