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Calculate the standard deviation for the given frequency distribution of study hours.

Mathematics

ScanSolve AI Answer

Answer

1.798

Step-by-step solution

5 steps

To calculate the standard deviation from a frequency distribution, we use the formula:

σ=∑fx2∑f−(∑fx∑f)2\sigma = \sqrt{\frac{\sum fx^2}{\sum f} - \left(\frac{\sum fx}{\sum f}\right)^2}

where xx represents the number of hours, ff represents the number of students (frequency), ∑f\sum f is the total number of students, and ∑fx\sum fx is the sum of (hours ×\times frequency).

First, let's organize the data and calculate the necessary sums:

Number of hours (xx)Number of students (ff)fxfxx2x^2fx2fx^2
01000
13313
236412
339927
45201680
563025150
62123672
7174949
Total∑f=24\sum f = 24∑fx=87\sum fx = 87∑fx2=393\sum fx^2 = 393
  1. Calculate the total number of students (∑f\sum f).

    ∑f=1+3+3+3+5+6+2+1=24\sum f = 1 + 3 + 3 + 3 + 5 + 6 + 2 + 1 = 24
  2. Calculate the sum of (hours ×\times frequency) (∑fx\sum fx).

    ∑fx=(0×1)+(1×3)+(2×3)+(3×3)+(4×5)+(5×6)+(6×2)+(7×1)\sum fx = (0 \times 1) + (1 \times 3) + (2 \times 3) + (3 \times 3) + (4 \times 5) + (5 \times 6) + (6 \times 2) + (7 \times 1) ∑fx=0+3+6+9+20+30+12+7=87\sum fx = 0 + 3 + 6 + 9 + 20 + 30 + 12 + 7 = 87
  3. Calculate the sum of (hours squared ×\times frequency) (∑fx2\sum fx^2).

    ∑fx2=(02×1)+(12×3)+(22×3)+(32×3)+(42×5)+(52×6)+(62×2)+(72×1)\sum fx^2 = (0^2 \times 1) + (1^2 \times 3) + (2^2 \times 3) + (3^2 \times 3) + (4^2 \times 5) + (5^2 \times 6) + (6^2 \times 2) + (7^2 \times 1) ∑fx2=(0×1)+(1×3)+(4×3)+(9×3)+(16×5)+(25×6)+(36×2)+(49×1)\sum fx^2 = (0 \times 1) + (1 \times 3) + (4 \times 3) + (9 \times 3) + (16 \times 5) + (25 \times 6) + (36 \times 2) + (49 \times 1) ∑fx2=0+3+12+27+80+150+72+49=393\sum fx^2 = 0 + 3 + 12 + 27 + 80 + 150 + 72 + 49 = 393
  4. Calculate the mean (xˉ\bar{x}).

    xˉ=∑fx∑f=8724=3.625\bar{x} = \frac{\sum fx}{\sum f} = \frac{87}{24} = 3.625
  5. Substitute the values into the standard deviation formula.

    σ=∑fx2∑f−(∑fx∑f)2\sigma = \sqrt{\frac{\sum fx^2}{\sum f} - \left(\frac{\sum fx}{\sum f}\right)^2} σ=39324−(8724)2\sigma = \sqrt{\frac{393}{24} - \left(\frac{87}{24}\right)^2} σ=16.375−(3.625)2\sigma = \sqrt{16.375 - (3.625)^2} σ=16.375−13.140625\sigma = \sqrt{16.375 - 13.140625} σ=3.234375\sigma = \sqrt{3.234375} σ≈1.7984368\sigma \approx 1.7984368

    Rounding to three decimal places:

    σ≈1.798\sigma \approx 1.798

    The standard deviation is 1.798.

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