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Calculate the sum sum_n=05 n(n+1)

Mathematics

ScanSolve AI Answer

Answer

70

Step-by-step solution

3 steps

Here's the solution for the summation:

  1. Expand the term inside the summation.

    The expression is n(n+1)n(n+1).

    n(n+1)=n2+nn(n+1) = n^2 + n
  2. Calculate each term for nn from 0 to 5.

    For n=0:0(0+1)=0×1=0n=0: 0(0+1) = 0 \times 1 = 0
    For n=1:1(1+1)=1×2=2n=1: 1(1+1) = 1 \times 2 = 2
    For n=2:2(2+1)=2×3=6n=2: 2(2+1) = 2 \times 3 = 6
    For n=3:3(3+1)=3×4=12n=3: 3(3+1) = 3 \times 4 = 12
    For n=4:4(4+1)=4×5=20n=4: 4(4+1) = 4 \times 5 = 20
    For n=5:5(5+1)=5×6=30n=5: 5(5+1) = 5 \times 6 = 30

  3. Sum all the calculated terms.

    ∑n=05n(n+1)=0+2+6+12+20+30\sum_{n=0}^{5} n(n+1) = 0 + 2 + 6 + 12 + 20 + 30 =70= 70

    The sum is 70.

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