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Surface area of the open funnel in the shape of a cone of radius 3.5cm and slanting length of 10cm.

Mathematics

ScanSolve AI Answer

Answer

110 cm2110 \text{ cm}^2

Step-by-step solution

4 steps
  1. Tambua vipimo vilivyotolewa.

    Tunapewa rediasi ya koni, r=3.5 cmr = 3.5 \text{ cm}, na urefu mteremko, l=10 cml = 10 \text{ cm}.

  2. Andika fomula ya eneo la uso wa pembeni (lateral surface area) ya koni.

    Kwa kuwa faneli ni wazi (haina msingi), tunahitaji tu eneo la uso wa pembeni. Fomula ni:

    A=πrlA = \pi r l
  3. Badilisha thamani za rr na ll kwenye fomula.

    Tutatumia π≈227\pi \approx \frac{22}{7} kwa hesabu rahisi.

    A=227×3.5 cm×10 cmA = \frac{22}{7} \times 3.5 \text{ cm} \times 10 \text{ cm}
  4. Fanya hesabu.

    A=227×72 cm×10 cmA = \frac{22}{7} \times \frac{7}{2} \text{ cm} \times 10 \text{ cm} A=11×10 cm2A = 11 \times 10 \text{ cm}^2 A=110 cm2A = 110 \text{ cm}^2

    Eneo la uso wa faneli ni:

    110 cm2110 \text{ cm}^2
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