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Solve the system of linear equations: 2a + 3b + 4c = 11, a + 5b + c = 15, 3a + 11b + 13 = 25.

Mathematics

ScanSolve AI Answer

Here are the given equations:

  1. 2a+3b+4c=112a + 3b + 4c = 11
  2. a+5b+c=15a + 5b + c = 15
  3. 3a+11b+13=253a + 11b + 13 = 25

First, simplify equation (3) by moving the constant term to the right side:
3a+11b=25−133a + 11b = 25 - 13
3a+11b=123a + 11b = 12 (Equation 3 simplified)

Now we have the system of equations:

  1. 2a+3b+4c=112a + 3b + 4c = 11
  2. a+5b+c=15a + 5b + c = 15
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