Solve the system of linear equations: 2a + 3b + 4c = 11, a + 5b + c = 15, 3a + 11b + 13 = 25.

May 17, 2026Mathematics

ScanSolve AI Answer

May 17, 2026

Answer

11$

Here are the given equations:

$2a + 3b + 4c = 11$
$a + 5b + c = 15$
$3a + 11b + 13 = 25$

First, simplify equation (3) by moving the constant term to the right side: $3a + 11b = 25 - 13$ $3a + 11b = 12$ (Equation 3 simplified)

Now we have the system of equations:

$2a + 3b + 4c = 11$
$a + 5b + c = 15$

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1) 2a + 3b + 4c = 11 2) a + 5b + c = 15 3) 3a + 11b + 13 = 25 First, simplify equation (3) by moving the constant term to the right side: 3a + 11b = 25 - 13 3a + 11b = 12 (Equation 3 simplified) Now we have the system of equations: 1) 2a + 3b + 4c = 1…

Asked on May 17, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on May 17, 2026

Here are the given equations: 1) 2a + 3b + 4c = 11 2) a + 5b + c = 15 3) 3a + 11b + 13 = 25 First, simplify equation (3) by moving the constant term to the right side: 3a + 11b = 25 - 13 3a + 11b = 12 (Equation 3 simplified) Now we have the system of equations: 1) 2a + 3b + 4c = 11 2) a + 5b + c = 15