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Tafuta eneo la mchoro huu (25cm, 24cm)

July 29, 2026Mathematics

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\text{84 cm}^2

3 steps

Tambua pande za pembetatu.
Tunapewa pembetatu ya pembe mraba.
Urefu wa msingi ( $b$ ) ni $24 \text{ cm}$ .
Urefu wa kizingo ( $c$ ) ni $25 \text{ cm}$ .
Tunahitaji kupata urefu ( $a$ ) wa pembetatu.
Tumia kanuni ya Pythagoras kupata urefu ( $a$ ).
Kanuni ya Pythagoras inasema $a^2 + b^2 = c^2$ .
$a^2 + (24 \text{ cm})^2 = (25 \text{ cm})^2$ $a^2 + 576 \text{ cm}^2 = 625 \text{ cm}^2$ $a^2 = 625 \text{ cm}^2 - 576 \text{ cm}^2$ $a^2 = 49 \text{ cm}^2$ $a = \sqrt{49 \text{ cm}^2}$ $a = 7 \text{ cm}$
Hivyo, urefu wa pembetatu ni $7 \text{ cm}$ .
Kokotoa eneo la pembetatu.
Eneo la pembetatu ( $A$ ) hutolewa na kanuni $A = \frac{1}{2} \times \text{msingi} \times \text{urefu}$ .
$A = \frac{1}{2} \times 24 \text{ cm} \times 7 \text{ cm}$ $A = 12 \text{ cm} \times 7 \text{ cm}$ $A = 84 \text{ cm}^2$
Eneo la mchoro huu ni $\text{84 cm}^2$ .

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