Show that the expressions m(2-m) and m(-m+2) are equivalent by testing for m=1 and m=2.

Here are the solutions to questions 2.1.3 and 2.1.4.

Question 2

2.1.3
Based on your observations from 2.1.1 and 2.1.2, both expressions $m(2-m)$ and $m(-m+2)$ yielded the same result when $m=1$. This suggests that the two expressions might be equivalent.

2.1.4
Choose another value for $m$, and substitute in A and B. Do you get the same answer?

Let's choose $m=2$.

A) For $m(2 - m)$:
Substitute $m=2$:

$$2(2 - 2) = 2(0) = \boxed{0}$$

B) For $m(-m + 2)$:
Substitute $m=2$:

$$2(-2 + 2) = 2(0) = \boxed{0}$$

Yes, we get the same answer.