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The figure below is an arc of a circle with points A, B and C on the arc. Determine the coordinates of the centre of the circle.

Mathematics

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Answer

(-3, 2)

Step-by-step solution

4 steps

Huu hapa ni utatuzi wa swali la 11.

Swali la 11: Takwimu iliyo hapa chini ni sehemu ya duara yenye pointi A, B na C kwenye sehemu hiyo. Bainisha kuratibu za kituo cha duara (alama 4).
Pointi zilizopewa ni:
A(−3,5)(-3, 5)
B(0,2)(0, 2)
C(−3,−1)(-3, -1)

  1. Fafanua kuratibu za kituo cha duara.

    Acha kituo cha duara kiwe (h,k)(h, k). Umbali kutoka kituo hadi pointi yoyote kwenye duara ni sawa (radius). Hivyo, CA2=CB2=CC2CA^2 = CB^2 = CC^2.

  2. Unda milinganyo kwa kutumia fomula ya umbali.

    Tunatumia fomula ya umbali d2=(x2−x1)2+(y2−y1)2d^2 = (x_2 - x_1)^2 + (y_2 - y_1)^2.
    Kwanza, linganisha umbali wa mraba kutoka kituo hadi A na B (CA2=CB2CA^2 = CB^2):

    (h−(−3))2+(k−5)2=(h−0)2+(k−2)2(h - (-3))^2 + (k - 5)^2 = (h - 0)^2 + (k - 2)^2 (h+3)2+(k−5)2=h2+(k−2)2(h + 3)^2 + (k - 5)^2 = h^2 + (k - 2)^2

    Panua milinganyo:

    h2+6h+9+k2−10k+25=h2+k2−4k+4h^2 + 6h + 9 + k^2 - 10k + 25 = h^2 + k^2 - 4k + 4

    Ondoa h2h^2 na k2k^2 kutoka pande zote mbili:

    6h−10k+34=−4k+46h - 10k + 34 = -4k + 4

    Panga upya ili kupata mlinganyo wa kwanza:

    6h−10k+4k=4−346h - 10k + 4k = 4 - 34 6h−6k=−306h - 6k = -30

    Gawanya kwa 6:

    h−k=−5(Mlinganyo 1)h - k = -5 \quad \text{(Mlinganyo 1)}

    Pili, linganisha umbali wa mraba kutoka kituo hadi B na C (CB2=CC2CB^2 = CC^2):

    (h−0)2+(k−2)2=(h−(−3))2+(k−(−1))2(h - 0)^2 + (k - 2)^2 = (h - (-3))^2 + (k - (-1))^2 h2+(k−2)2=(h+3)2+(k+1)2h^2 + (k - 2)^2 = (h + 3)^2 + (k + 1)^2

    Panua milinganyo:

    h2+k2−4k+4=h2+6h+9+k2+2k+1h^2 + k^2 - 4k + 4 = h^2 + 6h + 9 + k^2 + 2k + 1

    Ondoa h2h^2 na k2k^2 kutoka pande zote mbili:

    −4k+4=6h+2k+10-4k + 4 = 6h + 2k + 10

    Panga upya ili kupata mlinganyo wa pili:

    0=6h+2k+4k+10−40 = 6h + 2k + 4k + 10 - 4 0=6h+6k+60 = 6h + 6k + 6

    Gawanya kwa 6:

    h+k=−1(Mlinganyo 2)h + k = -1 \quad \text{(Mlinganyo 2)}
  3. Tatua mfumo wa milinganyo.

    Tuna milinganyo miwili ya mstari:

    1. h−k=−5h - k = -5
    2. h+k=−1h + k = -1

    Ongeza Mlinganyo 1 na Mlinganyo 2:

    (h−k)+(h+k)=−5+(−1)(h - k) + (h + k) = -5 + (-1) 2h=−62h = -6 h=−3h = -3
  4. Tafuta thamani ya kk.

    Badilisha h=−3h = -3 kwenye Mlinganyo 2:

    −3+k=−1-3 + k = -1 k=−1+3k = -1 + 3 k=2k = 2

    Kuratibu za kituo cha duara ni (−3,2)(-3, 2).

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