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The following are students' scores in a Mathematics test. What is the probability that a student scored:

Mathematics

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Answers

5 parts
a

18\frac{1}{8}

b

14\frac{1}{4}

c

516\frac{5}{16}

d

1116\frac{11}{16}

e

12\frac{1}{2}

Step-by-step solution

10 steps

First, let's list all the scores and find the total number of scores.
The scores are: $9, 8, 6, 10, 7, 10, 5, 6, 3, 3, 4, 2, 4, 2, 4, 4$.
Total number of scores = 16.

Part a· 2 steps

Probability that a student scored 3 marks?

  1. Count the number of times '3' appears in the scores.

    The scores '3' appear 2 times.

  2. Calculate the probability.

    P(score of 3)=Number of scores of 3Total number of scores=216=18P(\text{score of 3}) = \frac{\text{Number of scores of 3}}{\text{Total number of scores}} = \frac{2}{16} = \frac{1}{8}

    The probability of scoring 3 marks is 18\boxed{\frac{1}{8}}.

Part b

14\frac{1}{4}

Probability that a student scored 4 marks?

  1. Count the number of times '4' appears in the scores.

    The scores '4' appear 4 times.

  2. Calculate the probability.

    P(score of 4)=Number of scores of 4Total number of scores=416=14P(\text{score of 4}) = \frac{\text{Number of scores of 4}}{\text{Total number of scores}} = \frac{4}{16} = \frac{1}{4}

    The probability of scoring 4 marks is 14\boxed{\frac{1}{4}}.

Part c

516\frac{5}{16}

Probability that a student scored an odd mark?

  1. Identify and count the odd marks.

    The odd marks are $9, 7, 5, 3, 3$.
    There are 5 odd marks.

  2. Calculate the probability.

    P(odd mark)=Number of odd marksTotal number of scores=516P(\text{odd mark}) = \frac{\text{Number of odd marks}}{\text{Total number of scores}} = \frac{5}{16}

    The probability of scoring an odd mark is 516\boxed{\frac{5}{16}}.

Part d

1116\frac{11}{16}

Probability that a student scored an even mark?

  1. Identify and count the even marks.

    The even marks are $8, 6, 10, 10, 6, 4, 2, 4, 2, 4, 4$.
    There are 11 even marks.

  2. Calculate the probability.

    P(even mark)=Number of even marksTotal number of scores=1116P(\text{even mark}) = \frac{\text{Number of even marks}}{\text{Total number of scores}} = \frac{11}{16}

    The probability of scoring an even mark is 1116\boxed{\frac{11}{16}}.

Part e

12\frac{1}{2}

Probability that a student scored a mark less than 5?

  1. Identify and count the marks less than 5.

    Marks less than 5 are $2, 3, 4$.
    From the list: $3, 3, 4, 2, 4, 2, 4, 4$.
    There are 8 marks less than 5.

  2. Calculate the probability.

    P(mark less than 5)=Number of marks less than 5Total number of scores=816=12P(\text{mark less than 5}) = \frac{\text{Number of marks less than 5}}{\text{Total number of scores}} = \frac{8}{16} = \frac{1}{2}

    The probability of scoring a mark less than 5 is 12\boxed{\frac{1}{2}}.

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