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Mathematics

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Here's how to calculate the area for kites C and D. Remember, the area of a kite is given by the formula:

Area=12×d1×d2\text{Area} = \frac{1}{2} \times d_1 \times d_2

where d1d_1 and d2d_2 are the lengths of the diagonals.

C)

  1. Identify the lengths of the diagonals for kite C.

    The horizontal diagonal (d1d_1) is 3 cm+2 cm=5 cm3 \text{ cm} + 2 \text{ cm} = 5 \text{ cm}.
    The vertical diagonal (d2d_2) is 3 cm+3 cm=6 cm3 \text{ cm} + 3 \text{ cm} = 6 \text{ cm}.

  2. Substitute the diagonal lengths into the area formula.

    AreaC=12×5 cm×6 cm\text{Area}_C = \frac{1}{2} \times 5 \text{ cm} \times 6 \text{ cm}
  3. Calculate the area.

    AreaC=12×30 cm2=15 cm2\text{Area}_C = \frac{1}{2} \times 30 \text{ cm}^2 = 15 \text{ cm}^2

    The area of kite C is 15 cm2\boxed{\text{15 cm}^2}.

    D)

  4. Identify the lengths of the diagonals for kite D.

    The horizontal diagonal (d1d_1) is 5 cm+5 cm=10 cm5 \text{ cm} + 5 \text{ cm} = 10 \text{ cm}.
    The vertical diagonal (d2d_2) is 8 cm+5 cm=13 cm8 \text{ cm} + 5 \text{ cm} = 13 \text{ cm}.

  5. Substitute the diagonal lengths into the area formula.

    AreaD=12×10 cm×13 cm\text{Area}_D = \frac{1}{2} \times 10 \text{ cm} \times 13 \text{ cm}
  6. Calculate the area.

    AreaD=12×130 cm2=65 cm2\text{Area}_D = \frac{1}{2} \times 130 \text{ cm}^2 = 65 \text{ cm}^2

    The area of kite D is 65 cm2\boxed{\text{65 cm}^2}.

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