The minute arm of a tower clock is 1.5 m long, which is the radius r.

Here's the solution for question 2.1: The minute arm of a tower clock is 1.5 m long, which is the radius r. A clock face has 12 hour marks. The total angle of a circle is 2 radians. The angle between each hour mark is (2)/(12) = ()/(6) radians. 2.1.1. The arc displacement in radians Step 1: Determine the number of intervals moved. The minute arm moves from 1 to 8. Number of intervals = 8 - 1 = 7 intervals. Step 2: Calculate the total angular displacement. The angular displacement is the number of intervals multiplied by the angle per interval. = 7 × ()/(6) rad = (7)/(6) rad ≈ (7 × 3.14159)/(6) rad ≈ 3.665 rad The arc displacement is (7)/(6) rad or approximately 3.665 rad. 2.1.2. The circumferential length produced by the tip of the arm Step 1: Use the formula for arc length. The circumferential length (arc length) s is given by s = r, where r is the radius and is the angular displacement in radians. Given r = 1.5 m and = (7)/(6) rad. Step 2: Calculate the circumferential length. s = 1.5 m × (7)/(6) rad s = (1.5 × 7)/(6) m s = (10.5)/(6) m s = 1.75 m s ≈ 1.75 × 3.14159 m s ≈ 5.498 m The circumferential length is 1.75 m or approximately 5.498 m. Send me the next one 📸