Solve for θ with restriction 0° < θ < 90° correct to one decimal place. a) sin θ = 1.9/2.6 b) 2 tan θ = 1 c) tan 20°/2 = 5.102 d) cos θ = sin 20° e) sin θ = tan 40°

.mliiisah🥷🏾🙌🏾🔥🔥, let's knock this out. We need to solve for in the range 0^ < < 90^ and round the answers to one decimal place. a) Solve for : = (1.9)/(2.6) Step 1: Calculate the value of the ratio. = (1.9)/(2.6) ≈ 0.730769 Step 2: Use the inverse sine function to find . = ^-1(0.730769) ≈ 46.959^ Step 3: Round to one decimal place. ≈ 47.0^ b) Solve for : 2 = 1 Step 1: Isolate . = (1)/(2) = 0.5 Step 2: Use the inverse tangent function to find . = ^-1(0.5) ≈ 26.565^ Step 3: Round to one decimal place. ≈ 26.6^ c) Solve for : The question as written is 20^ = (5.102)/(2), which does not contain . Assuming there was a typo and the question intended to be = (5.102)/(2). Step 1: Calculate the value of the ratio. = (5.102)/(2) = 2.551 Step 2: Use the inverse tangent function to find . = ^-1(2.551) ≈ 68.599^ Step 3: Round to one decimal place. ≈ 68.6^ d) Solve for : = 20^ Step 1: Use the complementary angle identity x = (90^ - x). = (90^ - 20^) = 70^ Step 2: Since 0^ < < 90^, we can equate the angles. = 70^ Step 3: Round to one decimal place. = 70.0^ e) Solve for : = 40^ Step 1: Calculate the value of 40^. 40^ ≈ 0.8390996 Step 2: Use the inverse sine function to find . = 0.8390996 = ^-1(0.8390996) ≈ 57.019^ Step 3: Round to one decimal place. ≈ 57.0^ Send me the next one 📸