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What is the side length of a square with a diagonal of 10 cm?

Mathematics

ScanSolve AI Answer

Answer

52 cm5\sqrt{2} \text{ cm}

Step-by-step solution

3 steps
  1. Identify the relationship between the side length and diagonal of a square.

    For a square with side length ss and diagonal dd, the Pythagorean theorem states:

    s2+s2=d2s^2 + s^2 = d^2 2s2=d22s^2 = d^2

    Solving for ss:

    s2=d22s^2 = \frac{d^2}{2} s=d22s = \sqrt{\frac{d^2}{2}} s=d2s = \frac{d}{\sqrt{2}}
  2. Substitute the given diagonal length into the formula.

    The diagonal length d=10d = 10 cm.

    s=102s = \frac{10}{\sqrt{2}}
  3. Rationalize the denominator and simplify.

    To rationalize the denominator, multiply the numerator and denominator by 2\sqrt{2}:

    s=102×22s = \frac{10}{\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}} s=1022s = \frac{10\sqrt{2}}{2} s=52s = 5\sqrt{2}

    The side length of the square is 525\sqrt{2} cm.

    s=52 cms = 5\sqrt{2} \text{ cm} s≈5×1.4142 cms \approx 5 \times 1.4142 \text{ cm} s≈7.071 cms \approx 7.071 \text{ cm}

    The side length of the square is 52 cm5\sqrt{2} \text{ cm}.

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