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What is the sum of interior angles of a polygon and problems involving supplementary angles and complex numbers?

Mathematics

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Step-by-step solution

15 steps

Here are the solutions to the problems.

47.

  1. Recall the formula for the sum of interior angles of a polygon.

    The sum of the interior angles of a polygon with nn sides is given by the formula:

    S=(n−2)×180∘S = (n-2) \times 180^\circ
  2. Set up the equation using the given sum.

    We are given that the sum of the interior angles is 1080∘1080^\circ.

    1080=(n−2)×1801080 = (n-2) \times 180
  3. Solve for nn.

    Divide both sides by 180:

    1080180=n−2\frac{1080}{180} = n-2 6=n−26 = n-2

    Add 2 to both sides:

    n=6+2n = 6+2 n=8n = 8
  4. Identify the polygon with n=8n=8 sides.

    A polygon with 8 sides is an octagon.
    The correct option is A.
    The name of the polygon is an Octagon\boxed{\text{Octagon}}.

    48.

  5. Define the angle and its supplement.

    Let the angle be θ\theta.
    The supplement of the angle is 180∘−θ180^\circ - \theta.

  6. Set up the equation based on the given condition.

    The problem states that the supplement of an angle is twice as large as the angle.

    180∘−θ=2θ180^\circ - \theta = 2\theta
  7. Solve for θ\theta.

    Add θ\theta to both sides of the equation:

    180∘=2θ+θ180^\circ = 2\theta + \theta 180∘=3θ180^\circ = 3\theta

    Divide by 3:

    θ=180∘3\theta = \frac{180^\circ}{3} θ=60∘\theta = 60^\circ

    The correct option is C.
    The measure of the angle is 60∘\boxed{60^\circ}.

    49.

  8. Rewrite the division as a fraction.

    (2−i)÷(1+2i)=2−i1+2i(2 - i) \div (1 + 2i) = \frac{2-i}{1+2i}
  9. Multiply the numerator and denominator by the conjugate of the denominator.

    The conjugate of 1+2i1+2i is 1−2i1-2i.

    2−i1+2i×1−2i1−2i\frac{2-i}{1+2i} \times \frac{1-2i}{1-2i}
  10. Perform the multiplication in the numerator.

    (2−i)(1−2i)=2(1)+2(−2i)−i(1)−i(−2i)(2-i)(1-2i) = 2(1) + 2(-2i) - i(1) - i(-2i) =2−4i−i+2i2= 2 - 4i - i + 2i^2

    Substitute i2=−1i^2 = -1:

    =2−5i+2(−1)= 2 - 5i + 2(-1) =2−5i−2= 2 - 5i - 2 =−5i= -5i
  11. Perform the multiplication in the denominator.

    This is in the form (a+bi)(a−bi)=a2+b2(a+bi)(a-bi) = a^2 + b^2.

    (1+2i)(1−2i)=12+22(1+2i)(1-2i) = 1^2 + 2^2 =1+4= 1 + 4 =5= 5
  12. Combine the simplified numerator and denominator.

    −5i5=−i\frac{-5i}{5} = -i

    The correct option is A.
    The simplified expression is −i\boxed{-i}.

    50.

  13. Write the given equation.

    y=mx+cy = mx + c
  14. Isolate the term containing mm.

    Subtract cc from both sides of the equation:

    y−c=mxy - c = mx
  15. Solve for mm.

    Divide both sides by xx:

    y−cx=m\frac{y-c}{x} = m

    So, m=y−cxm = \frac{y-c}{x}.
    The correct option is B.
    Making mm the subject of the equation gives m=y−cx\boxed{m = \frac{y-c}{x}}.

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