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What is the sum of the highest common factor of 100 and 150 together with the common factor of 200 and 250?

Mathematics

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Answers

4 parts
a

8\mathbf{8}

b

32\mathbf{32}

c

12\mathbf{12}

d

8\mathbf{8}

2×179\mathbf{2 \times 179}

100\mathbf{100}

Step-by-step solution

22 steps

Part a· 4 steps

Factors of 24 and 32

  1. Find the prime factorization of 24.

    24=2×12=2×2×6=2×2×2×3=23×324 = 2 \times 12 = 2 \times 2 \times 6 = 2 \times 2 \times 2 \times 3 = 2^3 \times 3
  2. Find the prime factorization of 32.

    32=2×16=2×2×8=2×2×2×4=2×2×2×2×2=2532 = 2 \times 16 = 2 \times 2 \times 8 = 2 \times 2 \times 2 \times 4 = 2 \times 2 \times 2 \times 2 \times 2 = 2^5
  3. Identify the common prime factors with the lowest power.

    The common prime factor is 2. The lowest power of 2 is 232^3.

  4. Calculate the Highest Common Factor (HCF).

    HCF(24,32)=23=8\text{HCF}(24, 32) = 2^3 = 8

    The HCF of 24 and 32 is 8\boxed{\mathbf{8}}.

Part b

32\mathbf{32}

Factors of 64 and 32

  1. Find the prime factorization of 64.

    64=2×32=2×25=2664 = 2 \times 32 = 2 \times 2^5 = 2^6
  2. Find the prime factorization of 32.

    32=2532 = 2^5
  3. Identify the common prime factors with the lowest power.

    The common prime factor is 2. The lowest power of 2 is 252^5.

  4. Calculate the HCF.

    HCF(64,32)=25=32\text{HCF}(64, 32) = 2^5 = 32

    The HCF of 64 and 32 is 32\boxed{\mathbf{32}}.

Part c

12\mathbf{12}

Factors of 48 and 36

  1. Find the prime factorization of 48.

    48=2×24=2×23×3=24×348 = 2 \times 24 = 2 \times 2^3 \times 3 = 2^4 \times 3
  2. Find the prime factorization of 36.

    36=2×18=2×2×9=2×2×3×3=22×3236 = 2 \times 18 = 2 \times 2 \times 9 = 2 \times 2 \times 3 \times 3 = 2^2 \times 3^2
  3. Identify the common prime factors with the lowest power.

    Common prime factors are 2 and 3. The lowest power of 2 is 222^2. The lowest power of 3 is 313^1.

  4. Calculate the HCF.

    HCF(48,36)=22×31=4×3=12\text{HCF}(48, 36) = 2^2 \times 3^1 = 4 \times 3 = 12

    The HCF of 48 and 36 is 12\boxed{\mathbf{12}}.

Part d

8\mathbf{8}

Factors of 72 and 32

  1. Find the prime factorization of 72.

    72=2×36=2×22×32=23×3272 = 2 \times 36 = 2 \times 2^2 \times 3^2 = 2^3 \times 3^2
  2. Find the prime factorization of 32.

    32=2532 = 2^5
  3. Identify the common prime factors with the lowest power.

    The common prime factor is 2. The lowest power of 2 is 232^3.

  4. Calculate the HCF.

    HCF(72,32)=23=8\text{HCF}(72, 32) = 2^3 = 8

    The HCF of 72 and 32 is 8\boxed{\mathbf{8}}.

    Problem solving

    1. Factorise 358.

  5. Divide 358 by the smallest prime number, 2.

    358÷2=179358 \div 2 = 179
  6. Determine if 179 is a prime number.

    We check for divisibility by prime numbers up to 179≈13.37\sqrt{179} \approx 13.37.
    Primes to check: 3, 5, 7, 11, 13.

    • 179 is not divisible by 3 (sum of digits 1+7+9=171+7+9=17, not divisible by 3).
    • 179 is not divisible by 5 (does not end in 0 or 5).
    • 179÷7=25179 \div 7 = 25 with a remainder of 4.
    • 179÷11=16179 \div 11 = 16 with a remainder of 3.
    • 179÷13=13179 \div 13 = 13 with a remainder of 10. Since 179 is not divisible by any prime number up to 13, it is a prime number.
  7. Write the prime factorization.

    358=2×179358 = 2 \times 179

    The prime factorization of 358 is 2×179\boxed{\mathbf{2 \times 179}}.

    2. What is the sum of the highest common factor of 100 and 150 together with the highest common factor of 200 and 250?

  8. Find the HCF of 100 and 150.

    Prime factorization of 100: 100=22×52100 = 2^2 \times 5^2
    Prime factorization of 150: 150=2×3×52150 = 2 \times 3 \times 5^2

    HCF(100,150)=21×52=2×25=50\text{HCF}(100, 150) = 2^1 \times 5^2 = 2 \times 25 = 50
  9. Find the HCF of 200 and 250.

    Prime factorization of 200: 200=23×52200 = 2^3 \times 5^2
    Prime factorization of 250: 250=2×53250 = 2 \times 5^3

    HCF(200,250)=21×52=2×25=50\text{HCF}(200, 250) = 2^1 \times 5^2 = 2 \times 25 = 50
  10. Calculate the sum of the two HCFs.

    Sum=50+50=100\text{Sum} = 50 + 50 = 100

    The sum is 100\boxed{\mathbf{100}}.

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