The volume,V of a cylinder varies jointly as its height (h), and the square of its radius, (r). Calculate the percentage increase in its volume V when the radius increases by 5% and height h increases by 10%.

Mathematics

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Answer

Ongezeko la asilimia=∗21.275%\text{Ongezeko la asilimia} = *21.275\%

Step-by-step solution

4 steps
  1. Andika fomula ya ujazo wa awali.

    Ujazo VV unabadilika kwa pamoja na urefu wake hh na mraba wa eneo lake rr. Hii inamaanisha kuna kigezo cha uwiano kk.

    V1=kh1r12V_1 = k h_1 r_1^2

    Ambapo V1V_1 ni ujazo wa awali, h1h_1 ni urefu wa awali, na r1r_1 ni eneo la awali.

  2. Kokotoa eneo jipya na urefu mpya.

    Eneo rr linaongezeka kwa 5%, hivyo eneo jipya r2r_2 ni:

    r2=r1+0.05r1=1.05r1r_2 = r_1 + 0.05r_1 = 1.05r_1

    Urefu hh unaongezeka kwa 10%, hivyo urefu mpya h2h_2 ni:

    h2=h1+0.10h1=1.10h1h_2 = h_1 + 0.10h_1 = 1.10h_1
  3. Kokotoa ujazo mpya V2V_2.

    Tumia fomula ya ujazo na maadili mapya ya h2h_2 na r2r_2:

    V2=kh2r22V_2 = k h_2 r_2^2 V2=k(1.10h1)(1.05r1)2V_2 = k (1.10h_1) (1.05r_1)^2 V2=k(1.10h1)(1.052r12)V_2 = k (1.10h_1) (1.05^2 r_1^2) V2=k(1.10h1)(1.1025r12)V_2 = k (1.10h_1) (1.1025 r_1^2) V2=(1.10×1.1025)kh1r12V_2 = (1.10 \times 1.1025) k h_1 r_1^2 V2=1.21275kh1r12V_2 = 1.21275 k h_1 r_1^2

    Kutoka Step 1, tunajua V1=kh1r12V_1 = k h_1 r_1^2. Hivyo,

    V2=1.21275V1V_2 = 1.21275 V_1
  4. Kokotoa asilimia ya ongezeko la ujazo.

    Asilimia ya ongezeko inapatikana kwa fomula: V2−V1V1×100%\frac{V_2 - V_1}{V_1} \times 100\%.

    Ongezeko la asilimia=1.21275V1−V1V1×100%\text{Ongezeko la asilimia} = \frac{1.21275 V_1 - V_1}{V_1} \times 100\% Ongezeko la asilimia=(1.21275−1)V1V1×100%\text{Ongezeko la asilimia} = \frac{(1.21275 - 1)V_1}{V_1} \times 100\% Ongezeko la asilimia=0.21275×100%\text{Ongezeko la asilimia} = 0.21275 \times 100\% Ongezeko la asilimia=21.275%\text{Ongezeko la asilimia} = 21.275\%

    Asilimia ya ongezeko katika ujazo ni 21.275%.

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