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This is a set of math problems covering Roman numerals, subtraction, prime factorization, HCF, and LCM.

Mathematics

ScanSolve AI Answer

Step-by-step solution

15 steps

Here are the solutions to the questions:

1. Express DXIV in Arabic numerals.

  1. Break down the Roman numeral into its components.

    D = 500
    X = 10
    IV = 4 (since I (1) comes before V (5), it means 5−1=45 - 1 = 4)

  2. Add the values.

    500+10+4=514500 + 10 + 4 = 514

    The final answer is b) 514\boxed{\text{b) 514}}

    2. Subtract 1543 from 2993.

  3. Set up the subtraction.

    We need to calculate 2993−15432993 - 1543.

  4. Perform the subtraction.

    2993−1543=14502993 - 1543 = 1450

    The final answer is a) 1450\boxed{\text{a) 1450}}

    3. Which of the following represents the prime factors of 30?

  5. Find the prime factors of 30.

    A prime factor is a prime number that divides the given number exactly.
    Divide 30 by the smallest prime number, 2:
    30÷2=1530 \div 2 = 15
    Divide 15 by the smallest prime number that divides it, which is 3:
    15÷3=515 \div 3 = 5
    5 is a prime number.

  6. List the prime factors.

    The prime factors of 30 are 2, 3, and 5.

    The final answer is a) 2, 3, 5\boxed{\text{a) 2, 3, 5}}

    4. The H.C.F. of 13 and 39 is ......

  7. List the factors of each number.

    Factors of 13: 1, 13 (13 is a prime number)
    Factors of 39: 1, 3, 13, 39

  8. Identify the common factors.

    The common factors are 1 and 13.

  9. Determine the highest common factor (H.C.F.).

    The highest common factor is 13.

    The final answer is d) 13\boxed{\text{d) 13}}

    5. Which of the following is the least common multiple of 6, 5 and 4?

  10. Find the prime factorization of each number.

    6=2×36 = 2 \times 3
    5=55 = 5 (5 is a prime number)
    4=2×2=224 = 2 \times 2 = 2^2

  11. To find the L.C.M., take the highest power of each prime factor present in any of the numbers.

    The prime factors are 2, 3, and 5.
    Highest power of 2: 222^2 (from 4)
    Highest power of 3: 313^1 (from 6)
    Highest power of 5: 515^1 (from 5)

  12. Multiply these highest powers together.

    L.C.M.=22×3×5=4×3×5=12×5=60L.C.M. = 2^2 \times 3 \times 5 = 4 \times 3 \times 5 = 12 \times 5 = 60

    The final answer is c) 60\boxed{\text{c) 60}}

    6. What is 3.75+2.0001+6.30093.75 + 2.0001 + 6.3009?

  13. Align the decimal points and add the numbers.

       3.7500
       2.0001
    +  6.3009
    ---------
    
  14. Perform the addition column by column, starting from the rightmost digit.

    0+1+9=100 + 1 + 9 = 10 (write 0, carry 1)
    0+0+0+1(carry)=10 + 0 + 0 + 1 (\text{carry}) = 1
    5+0+0=55 + 0 + 0 = 5
    7+0+3=107 + 0 + 3 = 10 (write 0, carry 1)
    3+2+6+1(carry)=123 + 2 + 6 + 1 (\text{carry}) = 12

  15. Combine the results.

    3.75+2.0001+6.3009=12.05103.75 + 2.0001 + 6.3009 = 12.0510

    The final answer is a) 12.510\boxed{\text{a) 12.510}}

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