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To calculate the integral J = integral ((x)(x))/(^2(x)+1) dx, we can use a substitution method. The problem statement mentions "règle de Bioche" (Bioche's rule), which provides guideline

Mathematics

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To calculate the integral J=∫sin⁡(x)cos⁡(x)sin⁡2(x)+1dxJ = \int \frac{\sin(x)\cos(x)}{\sin^2(x)+1} dx, we can use a substitution method. The problem statement mentions "règle de Bioche" (Bioche's rule), which provides guidelines for substitutions in integrals involving trigonometric functions.

Let the integrand be ω(x)=sin⁡(x)cos⁡(x)sin⁡2(x)+1\omega(x) = \frac{\sin(x)\cos(x)}{\sin^2(x)+1}. We will check the conditions given by Bioche's rule:

  1. Check if ω(x)=ω(−x)\omega(x) = \omega(-x): $\omega(-x) = \frac{\sin(-x)\cos(-x)}{\sin^2(-x)+1} = \frac{-\sin(x)\
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