Evaluate the integral integral1.24.4 (2x2 + 3x - 1)/(sqrt(x+2)) dx using the Trapezium Rule with eight ordinates.

May 20, 2026Mathematics

ScanSolve AI Answer

May 20, 2026

Answer

8 \implies n = 7$ strips.

To evaluate the integral $\int_{1.2}^{4.4} \frac{2x^2 + 3x - 1}{\sqrt{x+2}} dx$ using the Trapezium Rule with eight ordinates, we first need to determine the step width $h$ .

Step 1: Determine the number of strips ( $n$ ) and the step width ( $h$ ). The number of ordinates is given as 8. In the Trapezium Rule, the number of ordinates is typically $n+1$ , where $n$ is the number of strips. So, $n+1 = 8 \implies n = 7$ strips. The limits of integration are $a = 1.2$ and $b = 4.4$ .

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The number of ordinates is given as 8.
In the Trapezium Rule, the number of ordinates is typically n+1, where n is the number of strips.
So, n+1 = 8 n = 7 strips.
The limits of integration are a = 1.2 and b = 4.4.

Asked on May 20, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on May 20, 2026

To evaluate the integral _1.2^4.4 (2x^2 + 3x - 1)/(sqrt(x+2)) dx using the Trapezium Rule with eight ordinates, we first need to determine the step width h. Step 1: Determine the number of strips (n) and the step width (h). The number of ordinates is given as 8. In the Trapezium Rule, the number of ordinates is typically n+1, where n is the number of strips. So, n+1 = 8 n = 7 strips. The limits of integration are a = 1.2 and b = 4.4.