To find the general term in the expansion of (2x + 3)⁵, we use the binomial theorem formula for the general term T_r+1 of (a+b)ⁿ:

To find the general term in the expansion of $(2x + 3)^5$, we use the binomial theorem formula for the general term $T_{r+1}$ of $(a+b)^n$:

$$T_{r+1} = \binom{n}{r} a^{n-r} b^r$$

In this expansion:

• $a = 2x$
• $b = 3$
• $n = 5$

Substitute these values into the formula:

$$T_{r+1} = \binom{5}{r} (2x)^{5-r} (3)^r$$

This expression represents the general term. Let's compare it with the given options.
The options are:

(a) $\binom{5}{r} (2x)^r$

(b) $\binom{5}{r} (2x)^{5-r} . 3^r$

(c) $\binom{5}{r} 2^r . 3^{5-r}$

(d) $\binom{5}{r} x^r . 3^{5-r}$

Our derived general term matches option (b).

The final answer is $\boxed{\text{(b)}}$.