To find the general term in the expansion of (2x+3)5, we use the binomial theorem formula for the general term Tr+1 of (a+b)n:
Tr+1=(rn)an−rbr
In this expansion:
• a=2x
• b=3
• n=5
Substitute these values into the formula:
Tr+1=(r5)(2x)5−r(3)r
This expression represents the general term. Let's compare it with the given options.
The options are:
(a) (r5)(2x)r
(b) (r5)(2x)5−r.3r
(c) (r5)2r.35−r
(d) (r5)xr.35−r
Our derived general term matches option (b).
The final answer is (b).