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Make an accurate drawing of the triangle and measure length d to 1 d.p.

Mathematics

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Answer

10.4 cm\text{10.4 cm}

Step-by-step solution

7 steps

To find the length dd, we will use the Law of Cosines, as we are given two sides and the included angle (SAS).

The Law of Cosines states:

d2=a2+b2−2abcos⁡(θ)d^2 = a^2 + b^2 - 2ab \cos(\theta)

where a=7.5a = 7.5 cm, b=8.9b = 8.9 cm, and θ=78∘\theta = 78^\circ.

  1. Substitute the given values into the formula.

    d2=(7.5)2+(8.9)2−2(7.5)(8.9)cos⁡(78∘)d^2 = (7.5)^2 + (8.9)^2 - 2(7.5)(8.9) \cos(78^\circ)
  2. Calculate the squares of the sides.

    (7.5)2=56.25(7.5)^2 = 56.25 (8.9)2=79.21(8.9)^2 = 79.21
  3. Calculate the product $2ab$.

    2(7.5)(8.9)=15×8.9=133.52(7.5)(8.9) = 15 \times 8.9 = 133.5
  4. Find the value of cos⁡(78∘)\cos(78^\circ).

    cos⁡(78∘)≈0.20791\cos(78^\circ) \approx 0.20791
  5. Substitute these values back into the equation for d2d^2.

    d2=56.25+79.21−133.5×0.20791d^2 = 56.25 + 79.21 - 133.5 \times 0.20791 d2=135.46−27.750285d^2 = 135.46 - 27.750285 d2=107.709715d^2 = 107.709715
  6. Take the square root to find dd.

    d=107.709715d = \sqrt{107.709715} d≈10.3783d \approx 10.3783
  7. Round the length dd to 1 decimal place.

    d≈10.4 cmd \approx 10.4 \text{ cm}

    To make an accurate drawing of the triangle:

    1. Draw a line segment of length 8.9 cm.
    2. At one end of this line segment, use a protractor to measure and mark an angle of 78∘78^\circ.
    3. From the vertex of the 78∘78^\circ angle, draw a line segment of length 7.5 cm along the 78∘78^\circ mark.
    4. Connect the end of the 8.9 cm line segment to the end of the 7.5 cm line segment. This third side is dd.
    5. Measure the length of side dd with a ruler. It should be approximately 10.4 cm.

    The measured length dd is:

    d=10.4 cmd = \boxed{\text{10.4 cm}}
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