To find the n^th term and the three terms of the arithmetic sequence, we first need to determine the common difference (d) and the first term (a₁).

In an arithmetic sequence, the $n^{th}$ term can be expressed as $a_n = a_k + (n-k)d$.
Using $a_8$ and $a_4$:

$$a_8 = a_4 + (8-4)d$$ $$a_8 = a_4 + 4d$$

Substitute the given values:

$$65 = 93 + 4d$$

Subtract 93 from both sides:

$$65 - 93 = 4d$$ $$-28 = 4d$$

Divide by 4:

$$d = \frac{-28}{4}$$ $$d = -7$$

The general formula for the $n^{th}$ term of an arithmetic sequence is $a_n = a_1 + (n-1)d$.
Using $a_4 = 93$ and $d = -7$:

$$a_4 = a_1 + (4-1)d$$ $$93 = a_1 + 3(-7)$$ $$93 = a_1 - 21$$

Add 21 to both sides:

$$a_1 = 93 + 21$$ $$a_1 = 114$$

Using the general formula $a_n = a_1 + (n-1)d$ with $a_1 = 114$ and $d = -7$:

$$a_n = 114 + (n-1)(-7)$$ $$a_n = 114 - 7n + 7$$ $$a_n = 121 - 7n$$

The first term is $a_1 = 114$.
The second term is $a_2 = a_1 + d = 114 + (-7) = 107$.
The third term is $a_3 = a_2 + d = 107 + (-7) = 100$.

The $n^{th}$ term of the arithmetic sequence is $\boxed{\text{121 - 7n}}$.
The first three terms of the sequence are $\boxed{\text{114, 107, 100}}$.