Triangle ABCD in FIGURE 3 below is drawn such that A = 30°; B = 90°; DC splits C such that angle θ and angle α are formed, also DC splits AB such that x and angle β are formed. BD = 10 cm and BC = 40 cm. Determine the following: 2.1.1. θ, 2.1.2. x, 2.1.3. α, 2.1.4. β, 2.1.5. AC, 2.1.6. AD
|Mathematics
Triangle ABCD in FIGURE 3 below is drawn such that A = 30°; B = 90°; DC splits C such that angle θ and angle α are formed, also DC splits AB such that x and angle β are formed. BD = 10 cm and BC = 40 cm. Determine the following: 2.1.1. θ, 2.1.2. x, 2.1.3. α, 2.1.4. β, 2.1.5. AC, 2.1.6. AD
ScanSolve AI Answer
Answer
\text{*14.04^\circ*}
Here are the solutions for the given problems:
2.1.1 Determine θ
Step 1: Identify the relevant right-angled triangle.
Consider △BDC. It is a right-angled triangle with ∠B=90∘.
The side opposite to θ is BD=10 cm.
The side adjacent to θ is BC=40 cm.
Step 2: Use the tangent function to find θ.
tanθ=adjacentopposite=BCBDtanθ=4010tanθ=41
Step 3: Calculate the value of θ.
θ=arctan(41)θ≈14.04∘
The value of θ is ∗14.04∘∗.
2.1.2 Determine x
Step 1: Refer to the problem statement and the diagram.
The problem states that BD=10 cm.
The diagram labels the length of the side BD as x.
Step 2: State the value of x.
x=10cm
The value of x is ∗10cm∗.
2.1.3 Determine α
Step 1: Find the total angle at C in the larger right-angled triangle.
Consider △ABC. It is a right-angled triangle with ∠B=90∘ and ∠A=30∘.
The sum of angles in a triangle is 180∘.
∠BCA=180∘−∠B−∠A∠BCA=180∘−90∘−30∘∠BCA=60∘
Step 2: Use the relationship between ∠BCA, α, and θ.
From the diagram, ∠BCA=α+θ.
We found θ≈14.04∘ in 2.1.1.
α=∠BCA−θα=60∘−14.036∘α≈45.96∘
The value of α is ∗45.96∘∗.
2.1.4 Determine β
Step 1: Identify the relevant triangle and known angles.
Consider △ADC. We know ∠A=30∘ and ∠ACD=α≈45.96∘.
The angle β is ∠ADC.
Step 2: Use the sum of angles in △ADC.
The sum of angles in a triangle is 180∘.
∠A+∠ACD+∠ADC=180∘30∘+α+β=180∘β=180∘−30∘−αβ=150∘−45.96∘β≈104.04∘
The value of β is ∗104.04∘∗.
2.1.5 Determine AC
Step 1: Identify the relevant right-angled triangle and known values.
Consider △ABC. It is a right-angled triangle with ∠B=90∘.
We know ∠A=30∘ and the side opposite to it, BC=40 cm.
AC is the hypotenuse.
Step 2: Use the sine function to find AC.
sinA=hypotenuseopposite=ACBCsin30∘=AC40
Step 3: Solve for AC.
AC=sin30∘40AC=0.540AC=80cm
The length of AC is ∗80cm∗.
2.1.6 Determine AD
Step 1: Find the length of the entire side AB.
Consider △ABC. We know ∠A=30∘, ∠B=90∘, and BC=40 cm.
We can use the tangent function.
tanA=adjacentopposite=ABBCtan30∘=AB40
Step 2: Solve for AB.
AB=tan30∘40AB=1/340AB=403cm
Step 3: Calculate AD.
From the diagram, D is a point on AB, so AD=AB−BD.
We know BD=x=10 cm from 2.1.2.
AD=403−10AD≈40(1.73205)−10AD≈69.282−10AD≈59.28cm
The length of AD is ∗(403−10)cm∗orapproximately∗59.28cm∗.
3 done, 2 left today. You're making progress.
Was this helpful?
Need help with your own homework?
Get instant step-by-step solutions to any question. Free to start.
Triangle ABCD in FIGURE 3 below is drawn such that A = 30°; B = 90°; DC splits C such that angle θ and angle α are formed, also DC splits AB such that x and angle β are formed. BD = 10 cm and BC = 40 cm. Determine the following: 2.1.1. θ, 2.1.2. x, 2.1.3. α, 2.1.4. β, 2.1.5. AC, 2.1.6. AD
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
Here are the solutions for the given problems: 2.1.1 Determine Step 1: Identify the relevant right-angled triangle. Consider BDC. It is a right-angled triangle with B = 90^. The side opposite to is BD = 10 cm. The side adjacent to is BC = 40 cm. Step 2: Use the tangent function to find . = oppositeadjacent = (BD)/(BC) = (10)/(40) = (1)/(4) Step 3: Calculate the value of . = ((1)/(4)) ≈ 14.04^ The value of is 14.04^. 2.1.2 Determine x Step 1: Refer to the problem statement and the diagram. The problem states that BD = 10 cm. The diagram labels the length of the side BD as x. Step 2: State the value of x. x = 10 cm The value of x is 10 cm. 2.1.3 Determine Step 1: Find the total angle at C in the larger right-angled triangle. Consider ABC. It is a right-angled triangle with B = 90^ and A = 30^. The sum of angles in a triangle is 180^. BCA = 180^ - B - A BCA = 180^ - 90^ - 30^ BCA = 60^ Step 2: Use the relationship between BCA, , and . From the diagram, BCA = + . We found ≈ 14.04^ in 2.1.1. = BCA - = 60^ - 14.036^ ≈ 45.96^ The value of is 45.96^. 2.1.4 Determine Step 1: Identify the relevant triangle and known angles. Consider ADC. We know A = 30^ and ACD = ≈ 45.96^. The angle is ADC. Step 2: Use the sum of angles in ADC. The sum of angles in a triangle is 180^. A + ACD + ADC = 180^ 30^ + + = 180^ = 180^ - 30^ - = 150^ - 45.96^ ≈ 104.04^ The value of is 104.04^. 2.1.5 Determine AC Step 1: Identify the relevant right-angled triangle and known values. Consider ABC. It is a right-angled triangle with B = 90^. We know A = 30^ and the side opposite to it, BC = 40 cm. AC is the hypotenuse. Step 2: Use the sine function to find AC. A = oppositehypotenuse = (BC)/(AC) 30^ = (40)/(AC) Step 3: Solve for AC. AC = (40)/( 30^) AC = (40)/(0.5) AC = 80 cm The length of AC is 80 cm. 2.1.6 Determine AD Step 1: Find the length of the entire side AB. Consider ABC. We know A = 30^, B = 90^, and BC = 40 cm. We can use the tangent function. A = oppositeadjacent = (BC)/(AB) 30^ = (40)/(AB) Step 2: Solve for AB. AB = (40)/( 30^) AB = (40)/(1/sqrt(3)) AB = 40sqrt(3) cm Step 3: Calculate AD. From the diagram, D is a point on AB, so AD = AB - BD. We know BD = x = 10 cm from 2.1.2. AD = 40sqrt(3) - 10 AD ≈ 40(1.73205) - 10 AD ≈ 69.282 - 10 AD ≈ 59.28 cm The length of AD is (40sqrt(3) - 10) cm or approximately 59.28 cm. 3 done, 2 left today. You're making progress.