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Use the angle addition formula for sine.

Mathematics

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Answer

6+24\frac{\sqrt{6} + \sqrt{2}}{4}

Step-by-step solution

4 steps
  1. Use the angle addition formula for sine.

    We can express 75∘75^\circ as the sum of two standard angles, 45∘+30∘45^\circ + 30^\circ.
    The addition formula for sine is sin⁡(A+B)=sin⁡Acos⁡B+cos⁡Asin⁡B\sin(A+B) = \sin A \cos B + \cos A \sin B.

  2. Substitute A=45∘A=45^\circ and B=30∘B=30^\circ into the formula.

    sin⁡75∘=sin⁡(45∘+30∘)=sin⁡45∘cos⁡30∘+cos⁡45∘sin⁡30∘\sin 75^\circ = \sin(45^\circ + 30^\circ) = \sin 45^\circ \cos 30^\circ + \cos 45^\circ \sin 30^\circ
  3. Substitute the known exact values for sin⁡45∘\sin 45^\circ, cos⁡30∘\cos 30^\circ, cos⁡45∘\cos 45^\circ, and sin⁡30∘\sin 30^\circ.

    We know that:
    sin⁡45∘=22\sin 45^\circ = \frac{\sqrt{2}}{2}
    cos⁡30∘=32\cos 30^\circ = \frac{\sqrt{3}}{2}
    cos⁡45∘=22\cos 45^\circ = \frac{\sqrt{2}}{2}
    sin⁡30∘=12\sin 30^\circ = \frac{1}{2}

    sin⁡75∘=(22)(32)+(22)(12)\sin 75^\circ = \left(\frac{\sqrt{2}}{2}\right)\left(\frac{\sqrt{3}}{2}\right) + \left(\frac{\sqrt{2}}{2}\right)\left(\frac{1}{2}\right)
  4. Multiply the terms and simplify.

    sin⁡75∘=2⋅34+2⋅14\sin 75^\circ = \frac{\sqrt{2} \cdot \sqrt{3}}{4} + \frac{\sqrt{2} \cdot 1}{4} sin⁡75∘=64+24\sin 75^\circ = \frac{\sqrt{6}}{4} + \frac{\sqrt{2}}{4} sin⁡75∘=6+24\sin 75^\circ = \frac{\sqrt{6} + \sqrt{2}}{4}

    The value of sin⁡75∘\sin 75^\circ in simple surd form is 6+24\boxed{\frac{\sqrt{6} + \sqrt{2}}{4}}.

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