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Using a ruler, a pencil and a pair of compasses only, construct a rhombus LMNO such that line LM = 6cm, angle LMN = 135°. Measure diagonal LN.

Mathematics

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Answer

11.1 cm11.1 \text{ cm}

Step-by-step solution

6 steps

Here are the steps to construct the rhombus LMNO and measure the diagonal LN:

  1. Draw the base line segment LM.

    Draw a straight line using a ruler. Mark a point L on it. From L, measure 6 cm along the line and mark point M. So, LM=6 cm\text{LM} = 6 \text{ cm}.

  2. Construct angle LMN = 135∘135^\circ at point M.

    • Extend the line segment LM to the right of M.
    • Place the compass at M and draw a semicircle that intersects LM (extended) at two points. Let's call the point on the extension P.
    • From P, with the same compass radius, mark an arc on the semicircle (this is 60∘60^\circ). From this new point, mark another arc (this is 120∘120^\circ). From this 120∘120^\circ mark, draw another arc.
    • Construct a perpendicular line at M (a 90∘90^\circ angle). To do this, from the 60∘60^\circ and 120∘120^\circ marks on the semicircle, draw arcs that intersect above M. Draw a line from M through this intersection. This line forms a 90∘90^\circ angle with LM.
    • The angle between the 90∘90^\circ line and the extended line (to the right of M) is 90∘90^\circ. Bisect this 90∘90^\circ angle. The bisector will form an angle of 45∘45^\circ with the 90∘90^\circ line.
    • The ray for 135∘135^\circ will be the line formed by adding this 45∘45^\circ to the 90∘90^\circ line, measured from LM. So, the angle ∠LMN=90∘+45∘=135∘\angle \text{LMN} = 90^\circ + 45^\circ = 135^\circ.
  3. Mark point N.

    • With M as the center and a radius of 6 cm (since all sides of a rhombus are equal), draw an arc that intersects the 135∘135^\circ ray constructed in Step 2. Mark this intersection point as N. So, MN=6 cm\text{MN} = 6 \text{ cm}.
  4. Locate point O.

    • With L as the center and a radius of 6 cm, draw an arc above LM.
    • With N as the center and a radius of 6 cm, draw another arc that intersects the previous arc. Mark this intersection point as O.
  5. Complete the rhombus.

    • Join points L to O and N to O with straight lines. You have now constructed the rhombus LMNO.
  6. Measure diagonal LN.

    • Draw a straight line connecting point L to point N.
    • Measure the length of the line segment LN using a ruler.

    Using the Law of Cosines for triangle LMN:

    LN2=LM2+MN2−2⋅LM⋅MN⋅cos⁡(∠LMN)\text{LN}^2 = \text{LM}^2 + \text{MN}^2 - 2 \cdot \text{LM} \cdot \text{MN} \cdot \cos(\angle \text{LMN}) LN2=62+62−2⋅6⋅6⋅cos⁡(135∘)\text{LN}^2 = 6^2 + 6^2 - 2 \cdot 6 \cdot 6 \cdot \cos(135^\circ) LN2=36+36−72⋅(−22)\text{LN}^2 = 36 + 36 - 72 \cdot \left(-\frac{\sqrt{2}}{2}\right) LN2=72+362\text{LN}^2 = 72 + 36\sqrt{2} LN=72+362\text{LN} = \sqrt{72 + 36\sqrt{2}} LN=36(2+2)\text{LN} = \sqrt{36(2 + \sqrt{2})} LN=62+2\text{LN} = 6\sqrt{2 + \sqrt{2}} LN≈62+1.4142\text{LN} \approx 6\sqrt{2 + 1.4142} LN≈63.4142\text{LN} \approx 6\sqrt{3.4142} LN≈6×1.8477\text{LN} \approx 6 \times 1.8477 LN≈11.086 cm\text{LN} \approx 11.086 \text{ cm}

    The measured length of diagonal LN is approximately 11.1 cm\boxed{11.1 \text{ cm}}.

    2 zimekamilika. Zimebaki 3 leo — tuma inayofuata.

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