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Using a scale of 2cm to 1 unit on both axes, draw the graph of y=2x+5 for the values of x from -3 to +4. 2. Find the size of the lettered angles. Give reasons for your answers. 3. Calculate the size of each angle of a regular Octagon.

Mathematics

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Graph of y = 2x + 5

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Key points of y = 2x + 5
Pointxy
x-intercept−2.50
y-intercept05

Step-by-step solution

4 steps
  1. Prepare for graphing y=2x+5y = 2x + 5.

    To draw the graph, first create a table of values for xx from −3-3 to 4.
    Substitute each xx value into the equation y=2x+5y = 2x + 5 to find the corresponding yy value.

    xx2x2x+5+5y=2x+5y = 2x + 5(x,y)(x, y)
    −3-3−6-6+5+5−1-1(−3,−1)(-3, -1)
    −2-2−4-4+5+51(−2,1)(-2, 1)
    −1-1−2-2+5+53(−1,3)(-1, 3)
    00+5+55(0,5)(0, 5)
    12+5+57(1,7)(1, 7)
    24+5+59(2,9)(2, 9)
    36+5+511(3,11)(3, 11)
    48+5+513(4,13)(4, 13)
  2. Plot the graph.

    • Draw two perpendicular axes, the xx-axis (horizontal) and the yy-axis (vertical).
    • Mark the origin (0,0)(0,0) where the axes intersect.
    • Apply the scale: 2 cm2 \text{ cm} represents 1 unit1 \text{ unit} on both axes. This means every 2 cm2 \text{ cm} grid line on your graph paper will be labeled as 1,2,3,…1, 2, 3, \dots for positive values and −1,−2,−3,…-1, -2, -3, \dots for negative values.
    • Plot the points from the table: (−3,−1),(−2,1),(−1,3),(0,5),(1,7),(2,9),(3,11),(4,13)(-3, -1), (-2, 1), (-1, 3), (0, 5), (1, 7), (2, 9), (3, 11), (4, 13).
    • Draw a straight line connecting all the plotted points. This line is the graph of y=2x+5y = 2x + 5.
  3. Find the size of the lettered angles.

    The diagram shows two parallel lines intersected by a transversal. The given angle is 72∘72^\circ.

    • Angle bb: Angles on a straight line sum to 180∘180^\circ.
    b=180∘−72∘=108∘b = 180^\circ - 72^\circ = \boxed{108^\circ}
    • Angle dd: Vertically opposite angles are equal.
    d=72∘d = \boxed{72^\circ}
    • Angle cc: Angles on a straight line sum to 180∘180^\circ.
    c=180∘−d=180∘−72∘=108∘c = 180^\circ - d = 180^\circ - 72^\circ = \boxed{108^\circ}

    (Alternatively, cc is vertically opposite to bb, so c=b=108∘c = b = 108^\circ)

    Since the lines are parallel:

    • Angle ee: Corresponding angles are equal.
    e=72∘e = \boxed{72^\circ}
    • Angle ff: Corresponding angles are equal.
    f=b=108∘f = b = \boxed{108^\circ}

    (Alternatively, ee and ff are angles on a straight line, so f=180∘−e=180∘−72∘=108∘f = 180^\circ - e = 180^\circ - 72^\circ = 108^\circ)

    • Angle gg: Vertically opposite angles are equal.
    g=e=72∘g = e = \boxed{72^\circ}

    (Alternatively, gg and dd are corresponding angles, so g=d=72∘g = d = 72^\circ)

    • Angle hh: Vertically opposite angles are equal.
    h=f=108∘h = f = \boxed{108^\circ}

    (Alternatively, hh and cc are corresponding angles, so h=c=108∘h = c = 108^\circ)

  4. Calculate the size of each angle of a regular octagon.

    A regular octagon has n=8n=8 sides.
    The formula for the sum of interior angles of a polygon is (n−2)×180∘(n-2) \times 180^\circ.
    The sum of interior angles of an octagon is:

    (8−2)×180∘=6×180∘=1080∘(8-2) \times 180^\circ = 6 \times 180^\circ = 1080^\circ

    For a regular polygon, all interior angles are equal. So, each interior angle is the sum divided by the number of sides.

    Each angle=1080∘8=135∘\text{Each angle} = \frac{1080^\circ}{8} = \boxed{135^\circ}
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