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Esi and Afi were to share 56 mangoes so that Esi has 8 mangoes less than Afi. What would be Afi's share?

Mathematics

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Step-by-step solution

9 steps

  1. Define variables for the shares.

    Let Afi's share be AA mangoes.
    Let Esi's share be EE mangoes.

  2. Set up equations based on the given information.

    The total number of mangoes is 56:

    A+E=56A + E = 56

    Esi has 8 mangoes less than Afi:

    E=A−8E = A - 8

  3. Substitute the second equation into the first equation.

    A+(A−8)=56A + (A - 8) = 56 2A−8=562A - 8 = 56

  4. Solve for AA.

    2A=56+82A = 56 + 8 2A=642A = 64 A=642A = \frac{64}{2} A=32A = 32

    Afi's share is 32 mangoes.

    The final answer is 32\boxed{\text{32}}.

  5. Calculate the contribution per worker.

    The Ho branch has 50 workers and realized GHC 60000. Since each worker contributes an equal amount, the contribution per worker is:

    Contribution per worker=Total amount from Ho branchNumber of workers in Ho branch\text{Contribution per worker} = \frac{\text{Total amount from Ho branch}}{\text{Number of workers in Ho branch}} Contribution per worker=6000050 GHC/worker\text{Contribution per worker} = \frac{60000}{50} \text{ GHC/worker} Contribution per worker=1200 GHC/worker\text{Contribution per worker} = 1200 \text{ GHC/worker}

  6. Calculate the total amount realized by the Kpando branch.

    The Kpando branch has 40 workers.

    Total amount from Kpando branch=Contribution per worker×Number of workers in Kpando branch\text{Total amount from Kpando branch} = \text{Contribution per worker} \times \text{Number of workers in Kpando branch} Total amount from Kpando branch=1200 GHC/worker×40 workers\text{Total amount from Kpando branch} = 1200 \text{ GHC/worker} \times 40 \text{ workers} Total amount from Kpando branch=48000 GHC\text{Total amount from Kpando branch} = 48000 \text{ GHC}

    The final answer is GHC 48,000.00\boxed{\text{GHC 48,000.00}}.

  7. Calculate the total age of the initial 9 students.

    The average age of 9 students is 25 years.

    Total age of 9 students=Average age×Number of students\text{Total age of 9 students} = \text{Average age} \times \text{Number of students} Total age of 9 students=25 years×9\text{Total age of 9 students} = 25 \text{ years} \times 9 Total age of 9 students=225 years\text{Total age of 9 students} = 225 \text{ years}

  8. Calculate the new total age after the new student joins.

    A new student who is 15 years old joins the class.

    New total age=Total age of 9 students+Age of new student\text{New total age} = \text{Total age of 9 students} + \text{Age of new student} New total age=225 years+15 years\text{New total age} = 225 \text{ years} + 15 \text{ years} New total age=240 years\text{New total age} = 240 \text{ years}

  9. Calculate the new average age for 10 students.

    The new number of students is 9+1=109 + 1 = 10.

    New average age=New total ageNew number of students\text{New average age} = \frac{\text{New total age}}{\text{New number of students}} New average age=240 years10\text{New average age} = \frac{240 \text{ years}}{10} New average age=24 years\text{New average age} = 24 \text{ years}

    The final answer is 24\boxed{\text{24}}.

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