What's the integral of ln(x) dx

Mathematics

ScanSolve AI Answer

Answer

xln⁡(x)−x+Cx\ln(x) - x + C

Step-by-step solution

4 steps

Okay, let's integrate ln⁡(x)\ln(x). This requires integration by parts.

  1. Set up integration by parts.

    We use the formula ∫u dv=uv−∫v du\int u\,dv = uv - \int v\,du.
    Let u=ln⁡(x)u = \ln(x) and dv=dxdv = dx.

  2. Find dudu and vv.

    Differentiate uu to find dudu:

    du=1x dxdu = \frac{1}{x}\,dx

    Integrate dvdv to find vv:

    v=∫dx=xv = \int dx = x
  3. Apply the integration by parts formula.

    Substitute uu, vv, dudu, and dvdv into the formula:

    ∫ln⁡(x) dx=(ln⁡(x))(x)−∫(x)(1x) dx\int \ln(x)\,dx = (\ln(x))(x) - \int (x)\left(\frac{1}{x}\right)\,dx
  4. Simplify and integrate the remaining term.

    ∫ln⁡(x) dx=xln⁡(x)−∫1 dx\int \ln(x)\,dx = x\ln(x) - \int 1\,dx ∫ln⁡(x) dx=xln⁡(x)−x+C\int \ln(x)\,dx = x\ln(x) - x + C

    The integral of ln⁡(x) dx\ln(x)\,dx is xln⁡(x)−x+C\boxed{x\ln(x) - x + C}.

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