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Determine whether or not the following vectors in R3 are linearly dependent: u = (1,2,5), v = (2,5,1), and w = (1,5,2).

Mathematics

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let's determine the linear dependence of these vectors.

3. Determine whether or not the following vectors in R3\mathbb{R}^3 are linearly dependent: u=(1,2,5)u = (1,2,5), v=(2,5,1)v = (2,5,1), and w=(1,5,2)w = (1,5,2).

To determine if the vectors are linearly dependent, we can form a matrix with these vectors as columns and calculate its determinant. If the determinant is zero, the vectors are linearly dependent. If it's non-zero, they are linearly independent.

  1. Form the matrix AA with the given vectors as columns.

    A=[121255512]A = \begin{bmatrix} 1 & 2 & 1 \\ 2 & 5 & 5 \\ 5 & 1 & 2 \end{bmatrix}
  2. Calculate the determinant of matrix AA.

    We will use cofactor expansion along the first row:

    det⁡(A)=1⋅det⁡[5512]−2⋅det⁡[2552]+1⋅det⁡[2551]\det(A) = 1 \cdot \det \begin{bmatrix} 5 & 5 \\ 1 & 2 \end{bmatrix} - 2 \cdot \det \begin{bmatrix} 2 & 5 \\ 5 & 2 \end{bmatrix} + 1 \cdot \det \begin{bmatrix} 2 & 5 \\ 5 & 1 \end{bmatrix}
  3. Compute the 2×22 \times 2 determinants.

    det⁡[5512]=(5⋅2)−(5⋅1)=10−5=5\det \begin{bmatrix} 5 & 5 \\ 1 & 2 \end{bmatrix} = (5 \cdot 2) - (5 \cdot 1) = 10 - 5 = 5 det⁡[2552]=(2⋅2)−(5⋅5)=4−25=−21\det \begin{bmatrix} 2 & 5 \\ 5 & 2 \end{bmatrix} = (2 \cdot 2) - (5 \cdot 5) = 4 - 25 = -21 det⁡[2551]=(2⋅1)−(5⋅5)=2−25=−23\det \begin{bmatrix} 2 & 5 \\ 5 & 1 \end{bmatrix} = (2 \cdot 1) - (5 \cdot 5) = 2 - 25 = -23
  4. Substitute these values back into the determinant formula and simplify.

    det⁡(A)=1⋅(5)−2⋅(−21)+1⋅(−23)\det(A) = 1 \cdot (5) - 2 \cdot (-21) + 1 \cdot (-23) det⁡(A)=5+42−23\det(A) = 5 + 42 - 23 det⁡(A)=47−23\det(A) = 47 - 23 det⁡(A)=24\det(A) = 24
  5. Conclude based on the determinant value.

    Since det⁡(A)=24≠0\det(A) = 24 \neq 0, the vectors are linearly independent.
    The vectors are linearly independent\boxed{\text{The vectors are linearly independent}}

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