X2-x3+2x2+x+1 by X-1 Synthetic method

Mathematics

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Answer

x2+2x+3+4x−1x^2 + 2x + 3 + \frac{4}{x-1}

We want to divide the polynomial x3−x2+2x2+x+1x^3 - x^2 + 2x^2 + x + 1 by x−1x-1. First, simplify the polynomial: x3+x2+x+1x^3 + x^2 + x + 1.

Using synthetic division with the root 1 from the divisor x−1x-1:

1 | 1   1   1   1
  |     1   2   3
  ----------------
    1   2   3   4

The coefficients of the quotient are 1,2,31, 2, 3, and the remainder is 4.

The quotient is x2+2x+3x^2 + 2x + 3 and the remainder is 4.

So, x3+x2+x+1x−1=x2+2x+3+4x−1\frac{x^3 + x^2 + x + 1}{x-1} = x^2 + 2x + 3 + \frac{4}{x-1}.

The final answer is x2+2x+3+4x−1x^2 + 2x + 3 + \frac{4}{x-1}.

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