A 12 kg block is on an inclined plane at 30 degrees. The coefficient of friction is 2/3. Calculate the normal force and the component of weight perpendicular to the plane.

Here's the solution for question 8:

Given:
Mass $m = 12 \text{ kg}$
Angle of inclination $\theta = 30^\circ$
Coefficient of friction $\mu = \frac{2}{3}$
Acceleration due to gravity $g = 10 \text{ m/s}^2$

Step 1: Calculate the components of the weight.
The weight of the body is $W = mg$.

$$W = 12 \text{ kg} \times 10 \text{ m/s}^2 = 120 \text{ N}$$

The component of weight perpendicular to the plane is $W_\perp = W \cos \theta$.

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