This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Here's how to solve the problem: Given: Electric field intensity, E = 3.0 × 10 N C^-1 Charge of an electron, q_e = 1.602 × 10^-19 C Mass of an electron, m_e = 9.109 × 10^-31 kg a) The force F on the electron in the region. Step 1: Use the formula for the force on a charge in an electric field. The force F experienced by a charge q in an electric field E is given by: F = qE Step 2: Substitute the given values into the formula. F = (1.602 × 10^-19 C) × (3.0 × 10 N C^-1) Step 3: Calculate the force. F = 4.806 × 10^-18 N The force on the electron is 4.806 × 10^-18 N. b) The acceleration of an electron when acted on the force. Step 1: Use Newton's second law of motion. Newton's second law states that force equals mass times acceleration (F = ma). Therefore, acceleration a can be found by: a = (F)/(m_e) Step 2: Substitute the calculated force and the mass of the electron into the formula. a = 4.806 × 10^-18 N9.109 × 10^-31 kg Step 3: Calculate the acceleration. a ≈ 0.5276 × 10^13 m/s^2 a ≈ 5.276 × 10^12 m/s^2 The acceleration of the electron is approximately 5.276 × 10^12 m/s^2. Send me the next one 📸