This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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a) i) A: Beryllium has a higher first ionization energy (IE) than lithium. Beryllium has a higher nuclear charge than lithium, and its valence electrons are in the same principal energy level (n=2). The increased nuclear charge pulls the electrons closer, requiring more energy to remove the first electron. Additionally, beryllium has a filled 2s subshell, which is more stable. B: The first ionization energy of boron is less than that of beryllium. Beryllium has a filled 2s subshell (1s^2 2s^2), which is very stable. Boron has its outermost electron in a 2p orbital (1s^2 2s^2 2p^1). The 2p electron in boron is at a slightly higher energy level and experiences more shielding from the 2s electrons, making it easier to remove than a 2s electron from beryllium. ii) Step 1: Determine the common hydride formula for each element based on its group and typical valency. • Lithium (Group 1): Forms LiH • Beryllium (Group 2): Forms BeH_2 • Boron (Group 13): Forms BH_3 (often dimerizes to B_2H_6) • Carbon (Group 14): Forms CH_4 • Nitrogen (Group 15): Forms NH_3 • Oxygen (Group 16): Forms H_2O • Fluorine (Group 17): Forms HF • Neon (Group 18): Does not typically form hydrides. | Element | Li | Be | B | C | N | O | F | Ne | | :------ | :-- | :--- | :--- | :--- | :--- | :---- | :-- | :-- | | Hydride | LiH | BeH_2 | BH_3 | CH_4 | NH_3 | H_2O | HF | None | iii) Step 1: Identify the hydrides that are neutral. • CH_4 (methane) is a neutral hydride. • BH_3 (borane) is also considered neutral, though it is electron-deficient and often dimerizes. The two elements that form neutral hydrides are Carbon and Boron. That's 2 down. 3 left today — send the next one.