A bullet of mass 22g travelling with a horizontal velocity of 300ms⁻¹ strikes a block of wood of mass 378g which rests on a rough horizontal surface. After the impact, the bullet and the block move together and come to rest when the block has travelled a distance of 5m. Calculate the coefficient of sliding friction between the block and the floor.

Physics
A bullet of mass 22g travelling with a horizontal velocity of 300ms⁻¹ strikes a block of wood of mass 378g which rests on a rough horizontal surface. After the impact, the bullet and the block move together and come to rest when the block has travelled a distance of 5m. Calculate the coefficient of sliding friction between the block and the floor.

ScanSolve AI Answer

Question 1: Given: Mass of bullet mb=10g=0.010kgm_b = 10 g = 0.010 \text{kg} Initial velocity of bullet ub=400m/su_b = 400 \text{m/s} Mass of block mw=290g=0.290kgm_w = 290 g = 0.290 \text{kg} Initial velocity of block uw=0m/su_w = 0 \text{m/s} Distance travelled after impact s=1.5ms = 1.5 \text{m} Final velocity after coming to rest vf=0m/sv_f = 0 \text{m/s} Acceleration due to gravity $g = 9.8 \text{m/

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