A block of mass 5kg rests on a horizontal surface the coefficient of friction The block & The surface is o.4. Find the frictional force (take g=9.8m/s square

Physics

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Step-by-step solution

3 steps
  1. Identify the knowns and unknowns.

    Knowns:
    Mass (mm) = 5 kg
    Coefficient of friction (μ\mu) = 0.4
    Acceleration due to gravity (gg) = 9.8 m/s²
    Unknown:
    Frictional force (FfF_f)

  2. Calculate the normal force (NN).

    On a horizontal surface, the normal force is equal to the gravitational force.

    N=m×gN = m \times g N=5 kg×9.8 m/s2N = 5 \, \text{kg} \times 9.8 \, \text{m/s}^2 N=49 NN = 49 \, \text{N}
  3. Calculate the frictional force (FfF_f).

    The formula for frictional force is:

    Ff=μ×NF_f = \mu \times N Ff=0.4×49 NF_f = 0.4 \times 49 \, \text{N} Ff=19.6 NF_f = 19.6 \, \text{N}

    The frictional force is 19.6 N.

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