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A car starts with a velocity of 10 m/s and comes to rest in 25 m. Calculate its acceleration.

Physics

ScanSolve AI Answer

Answer

−2 m/s2-2 \text{ m/s}^2

Step-by-step solution

4 steps

❌ Incorrect.

Your setup of the variables and the kinematic equation is correct, but there is an error in the algebraic manipulation to solve for aa.

  1. Identify the given values.

    • Initial velocity, U=10 m/sU = 10 \text{ m/s}
    • Final velocity, V=0 m/sV = 0 \text{ m/s} (comes to rest)
    • Displacement, S=25 mS = 25 \text{ m}
    • Acceleration, a=?a = ?
  2. Apply the kinematic equation.

    V2=U2+2aSV^2 = U^2 + 2aS
  3. Substitute the values.

    02=(10)2+2(a)(25)0^2 = (10)^2 + 2(a)(25) 0=100+50a0 = 100 + 50a
  4. Solve for aa.

    To isolate aa, first subtract 100 from both sides:

    −100=50a-100 = 50a

    Then, divide by 50:

    a=−10050a = \frac{-100}{50} a=−2 m/s2a = -2 \text{ m/s}^2

    The acceleration is −2 m/s2\boxed{-2 \text{ m/s}^2}. The negative sign indicates deceleration.

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