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A car starts with an initial velocity of 3 m/s and reaches a final velocity of 9 m/s in 4 seconds. Calculate the acceleration.

Physics

ScanSolve AI Answer

Answer

1.5 m/s2\text{1.5 m/s}^2

Step-by-step solution

4 steps
  1. Identify the given values.

    The initial velocity is u=3 m/su = 3 \text{ m/s}.
    The final velocity is v=9 m/sv = 9 \text{ m/s}.
    The time taken is t=4 st = 4 \text{ s}.

  2. Use the formula for uniform acceleration.

    Acceleration aa is defined as the change in velocity over time:

    a=v−uta = \frac{v - u}{t}
  3. Substitute the values into the formula.

    a=9 m/s−3 m/s4 sa = \frac{9 \text{ m/s} - 3 \text{ m/s}}{4 \text{ s}}
  4. Calculate the acceleration.

    a=6 m/s4 sa = \frac{6 \text{ m/s}}{4 \text{ s}} a=1.5 m/s2a = 1.5 \text{ m/s}^2

    The uniform acceleration of the car is 1.5 m/s2\text{1.5 m/s}^2.

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