A car accelerates uniformly from 3 m/s to 9 m/s in 4 seconds. What is its acceleration?

Step 1: Identify the given values. The initial velocity is u = 3 m/s. The final velocity is v = 9 m/s. The time taken is t = 4 s. Step 2: Use the formula for uniform acceleration. Acceleration a is defined as the change in velocity over time: a = (v − u)/(t) Step 3: Substitute the values into the formula. a = 9 m/s − 3 m/s4 s Step 4: Calculate the acceleration. a = 6 m/s4 s; a = 1.5 m/s² The uniform acceleration of the car is 1.5 m/s².

A car accelerates uniformly from 3 m/s to 9 m/s in 4 seconds. What is its acceleration?

Step 1: Identify the given values. The initial velocity is u = 3 m/s. The final velocity is v = 9 m/s. The time taken is t = 4 s. Step 2: Use the formula for uniform acceleration. Acceleration a is defined as the change in velocity over time: a = (v − u)/(t) Step 3: Substitute the values into the formula. a = 9 m/s − 3 m/s4 s Step 4: Calculate the acceleration. a = 6 m/s4 s; a = 1.5 m/s² The uniform acceleration of the car is 1.5 m/s².

Solved: A car accelerates uniformly from 3 m/s to 9 m/s in…

Identify the given values.
The initial velocity is $u = 3 \text{ m/s}$ .
The final velocity is $v = 9 \text{ m/s}$ .
The time taken is $t = 4 \text{ s}$ .
Use the formula for uniform acceleration.
Acceleration $a$ is defined as the change in velocity over time:
$a = \frac{v - u}{t}$
Substitute the values into the formula.
$a = \frac{9 \text{ m/s} - 3 \text{ m/s}}{4 \text{ s}}$
Calculate the acceleration.
$a = \frac{6 \text{ m/s}}{4 \text{ s}}$ $a = 1.5 \text{ m/s}^2$
The uniform acceleration of the car is $\text{1.5 m/s}^2$ .

A car accelerates uniformly from 3 m/s to 9 m/s in 4 seconds. What is its acceleration?

Answer

Step-by-step solution

Identify the given values.

Use the formula for uniform acceleration.

Substitute the values into the formula.

Calculate the acceleration.

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