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A car starts from rest and accelerates uniformly at 5 m/s² for 8 seconds. Calculate the distance it travels.

Physics

ScanSolve AI Answer

Answer

B

Step-by-step solution

4 steps
  1. Identify the given values.

    The car starts from rest, so the initial velocity is u=0 m/su = 0 \text{ m/s}.
    The acceleration is a=5 m/s2a = 5 \text{ m/s}^2.
    The time is t=8 st = 8 \text{ s}.

  2. Apply the kinematic equation for distance travelled.

    The formula relating initial velocity, acceleration, time, and distance is:

    s=ut+12at2s = ut + \frac{1}{2}at^2
  3. Substitute the values into the formula.

    s=(0 m/s)(8 s)+12(5 m/s2)(8 s)2s = (0 \text{ m/s})(8 \text{ s}) + \frac{1}{2}(5 \text{ m/s}^2)(8 \text{ s})^2
  4. Calculate the terms.

    s=0+12(5 m/s2)(64 s2)s = 0 + \frac{1}{2}(5 \text{ m/s}^2)(64 \text{ s}^2) s=12(320 m)s = \frac{1}{2}(320 \text{ m}) s=160 ms = 160 \text{ m}

    The total distance travelled is 160 m160 \text{ m}.

    Comparing this with the given options:
    A. 40 m
    B. 160 m
    C. 200 m
    D. 320 m

    The correct option is B.

    The final answer is B. 160 m\boxed{\text{B. 160 m}}.

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