A car starts from rest and accelerates uniformly to a velocity of 15 m/s in 20 s. Calculate its acceleration and the distance covered. Also, explain what happens to the car's kinetic energy during bra

$$15 \text{ m/s} = 0 \text{ m/s} + a \times 20 \text{ s}$$ $$15 \text{ m/s} = a \times 20 \text{ s}$$ $$a = \frac{15 \text{ m/s}}{20 \text{ s}}$$ $$a = 0.75 \text{ m/s}^2$$

The acceleration of the car is $\boxed{\text{0.75 m/s}^2}$.

iii) Step 1: Identify the given values and the formula for distance.
Given:
Initial velocity, $u = 0 \text{ m/s}$
Final velocity, $v = 15 \text{ m/s}$
Time, $t = 20 \text{ s}$
The formula for distance covered is $s = \frac{(u+v)}{2}t$.

$$s = \frac{(0 \text{ m/s} + 15 \text{ m/s})}{2} \times 20 \text{ s}$$ $$s = \frac{15 \text{ m/s}}{2} \times 20 \text{ s}$$ $$s = 7.5 \text{ m/s} \times 20 \text{ s}$$ $$s = 150 \text{ m}$$

The distance covered by the car is $\boxed{\text{150 m}}$.

B)

i) During the braking process, the car's kinetic energy is converted into heat energy (due to friction between brake pads and wheels) and sound energy.