This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Hey Senior, good to see you again. Step 1: Identify the given values. The charge is q = 3 × 10^-6 C. The velocity is v = 2 × 10^5 m/s. (Note: The unit in the question, m/s^2, is typically for acceleration. We will proceed assuming it's m/s for velocity, which is standard for this type of problem.) The magnetic field strength is B = 0.5 T. The charge moves perpendicular to the magnetic field, so the angle = 90^. Step 2: State the formula for magnetic force on a moving charge. The magnetic force F acting on a charge q moving with velocity v in a magnetic field B at an angle is given by: F = qvB Step 3: Substitute the values into the formula. Substitute the given values into the formula: F = (3 × 10^-6 C) × (2 × 10^5 m/s) × (0.5 T) × (90^) Step 4: Calculate the magnetic force. Since (90^) = 1: F = (3 × 10^-6) × (2 × 10^5) × (0.5) × 1 F = (3 × 2 × 0.5) × (10^-6 × 10^5) F = (6 × 0.5) × (10^-6+5) F = 3 × 10^-1 F = 0.3 N The magnetic force acting on the charge is 0.3 N. Send me the next one 📸