A current-carrying wire of length 0.80 m and current 5.0 A is placed in a magnetic field of 0.60 T…

Question

A current-carrying wire of length 0.80 m and current 5.0 A is placed in a magnetic field of 0.60 T perpendicular to the field. Calculate the force on the wire.

ScanSolve AI Tutor · Accepted Answer

Here's the solution for question 13:

Given:
Length of wire, $L = 0.80 \text{ m}$
Current, $I = 5.0 \text{ A}$
Magnetic field strength, $B = 0.60 \text{ T}$
The wire is perpendicular to the magnetic field, so $\theta = 90^\circ$ .

Recall the formula for the magnetic force on a current-carrying wire.
The formula is $F = BIL \sin \theta$ .
Substitute the given values into the formula.
Since the wire is perpendicular to the magnetic field, $\sin 90^\circ = 1$ .
$F = (0.60 \text{ T})(5.0 \text{ A})(0.80 \text{ m})(1)$
Calculate the force.
$F = (0.60 \times 5.0 \times 0.80) \text{ N}$ $F = (3.0 \times 0.80) \text{ N}$ $F = 2.4 \text{ N}$
The magnitude of the force on the wire is $2.4 \text{ N}$ .

A current-carrying wire of length 0.80 m and current 5.0 A is placed in a magnetic field of 0.60 T perpendicular to the field. Calculate the force on the wire.

Answer

Step-by-step solution

Recall the formula for the magnetic force on a current-carrying wire.

Substitute the given values into the formula.

Calculate the force.

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