Calculate the force on a current-carrying wire in a magnetic field for different angles.

In this case, $\theta = 90^\circ$.

$$\sin(90^\circ) = 1$$

Substitute the values into the formula:

$$F = (0.3 \, \text{T})(5 \, \text{A})(2 \, \text{m}) \sin(90^\circ)$$ $$F = (0.3 \times 5 \times 2 \times 1) \, \text{N}$$ $$F = 3 \, \text{N}$$

The force on the wire at a right angle to the field is $\boxed{\text{3 N}}$.

In this case, $\theta = 35^\circ$.
Substitute the values into the formula:

$$F = (0.3 \, \text{T})(5 \, \text{A})(2 \, \text{m}) \sin(35^\circ)$$ $$F = (3 \, \text{N}) \sin(35^\circ)$$ $$F \approx 3 \times 0.5736 \, \text{N}$$ $$F \approx 1.7208 \, \text{N}$$

Rounding to two decimal places, the force on the wire at $35^\circ$ to the field is $\boxed{\text{1.72 N}}$.

In this case, the wire is parallel to the magnetic field, so $\theta = 0^\circ$.

$$\sin(0^\circ) = 0$$

Substitute the values into the formula:

$$F = (0.3 \, \text{T})(5 \, \text{A})(2 \, \text{m}) \sin(0^\circ)$$ $$F = (3 \, \text{N}) \times 0$$ $$F = 0 \, \text{N}$$

The force on the wire along the field is $\boxed{\text{0 N}}$.