This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Step 1: Calculate the total volume of the cuboid. The dimensions of the cuboid are 4 cm, 3 cm, and 12 cm. V_cuboid = length × width × height V_cuboid = 4\, cm × 3\, cm × 12\, cm V_cuboid = 144\, cm^3 Step 2: Calculate the volume of the milk. The cuboid is three-quarter full of milk. V_milk = (3)/(4) × V_cuboid V_milk = (3)/(4) × 144\, cm^3 V_milk = 3 × 36\, cm^3 V_milk = 108\, cm^3 Step 3: Convert the volume of milk from cubic centimeters to cubic meters. We know that 1\, m = 100\, cm, so 1\, m^3 = (100\, cm)^3 = 1,000,000\, cm^3. V_milk = 108\, cm^3 × 1\, m^31,000,000\, cm^3 V_milk = 0.000108\, m^3 Step 4: Calculate the mass of the milk from its weight. The weight of the milk (W) is 2.5 N. We use the formula W = m × g, where m is mass and g is the acceleration due to gravity. We will use g = 9.81\, m/s^2. m_milk = (W)/(g) m_milk = 2.5\, N9.81\, m/s^2 m_milk ≈ 0.25484\, kg Step 5: Calculate the density of the milk. Density () is given by the formula = (m)/(V). _milk = m_milkV_milk _milk = 0.25484\, kg0.000108\, m^3 _milk ≈ 2359.6\, kg/m^3 Rounding to three significant figures: _milk ≈ 2360\, kg/m^3 The density of the milk is 2360 kg/m^3. What's next? 3 done, 2 left today. You're making progress.