A drum with a diameter of 1.5 m is rotating at 200 r/min. A brake is applied to the drum, absorbing 80 kW of power. Calculate the angular velocity of the drum and the brake torque transmitted.

Step 1: Calculate the angular velocity of the drum. The drum rotates at N = 200 r/min. The angular velocity ω in rad/s is given by: ω = (2 π N)/(60); ω = (2 π × 200)/(60) = (400 π)/(60) = (20 π)/(3) rad/s ω ≈ 20.944 rad/s Step 2: Calculate the brake torque transmitted (2.1). The power absorbed P = 80 kW

A drum with a diameter of 1.5 m is rotating at 200 r/min. A brake is applied to the drum, absorbing 80 kW of power. Calculate the angular velocity of the drum and the brake torque transmitted.

Step 1: Calculate the angular velocity of the drum. The drum rotates at N = 200 r/min. The angular velocity ω in rad/s is given by: ω = (2 π N)/(60); ω = (2 π × 200)/(60) = (400 π)/(60) = (20 π)/(3) rad/s ω ≈ 20.944 rad/s Step 2: Calculate the brake torque transmitted (2.1). The power absorbed P = 80 kW

Solved: A drum with a diameter of 1.5 m is rotating at 200…

The drum rotates at $N = 200$ r/min.
The angular velocity $\omega$ in rad/s is given by:

\omega = \frac{2 \pi N}{60}

\omega = \frac{2 \pi \times 200}{60} = \frac{400 \pi}{60} = \frac{20 \pi}{3} \text{ rad/s}

\omega \approx 20.944 \text{ rad/s}

A drum with a diameter of 1.5 m is rotating at 200 r/min. A brake is applied to the drum, absorbing 80 kW of power. Calculate the angular velocity of the drum and the brake torque transmitted.

Step-by-step solution

Calculate the angular velocity of the drum.

Calculate the brake torque transmitted (2.1).

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