A drum with a diameter of 1.5 m is rotating at 200 r/min. A brake is applied to the drum, absorbing 80 kW of power. Calculate the angular velocity of the drum and the brake torque transmitted.

March 31, 2026Physics

ScanSolve AI Answer

March 31, 2026

Answer

200$ r/min.

Step 1: Calculate the angular velocity of the drum. The drum rotates at $N = 200$ r/min. The angular velocity $\omega$ in rad/s is given by: $\omega = \frac{2 \pi N}{60}$ $\omega = \frac{2 \pi \times 200}{60} = \frac{400 \pi}{60} = \frac{20 \pi}{3} rad/s$ $\omega \approx 20.944 rad/s$

Step 2: Calculate the brake torque transmitted (2.1). The power absorbed $P = 80$ kW

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Quick Answer

Calculate the angular velocity of the drum. The drum rotates at N = 200 r/min.

Asked on March 31, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

ScanSolve AI AnswerAnswered on March 31, 2026

Step 1: Calculate the angular velocity of the drum. The drum rotates at N = 200 r/min. The angular velocity in rad/s is given by: = (2 N)/(60) = (2 × 200)/(60) = (400 )/(60) = (20 )/(3) rad/s ≈ 20.944 rad/s Step 2: Calculate the brake torque transmitted (2.1). The power absorbed P = 80 kW